如何从excel文件填充django manytomany数据库

问题描述 投票:1回答:2

我正在尝试将数据从excel文件传输到我的sqlite3数据库中的manytomany表。

model.朋友

from django.db import models


class Major(models.Model):
    name = models.CharField(max_length=30, db_index=True)

class School(models.Model):
    name = models.CharField(max_length=50, db_index=True)
    majors = models.ManyToManyField(Major)


class professor(models.Model):
    ProfessorIDS = models.IntegerField()
    ProfessorName = models.CharField(max_length=100)
    ProfessorRating = models.DecimalField(decimal_places=2,max_digits=4)
    NumberofRatings = models.CharField(max_length=50)
    #delete major from the model  
    school = models.ForeignKey(School , on_delete=models.CASCADE)
    major = models.ForeignKey(Major , on_delete=models.CASCADE)

    def __str__(self):
        return self.ProfessorName

填充脚本

# populate.py, school_major_link
import os
import django
from django_xlspopulator.populator import Populator
os.environ.setdefault('DJANGO_SETTINGS_MODULE','blog_project.settings')
django.setup()
from locate.models import Major

pop = Populator('C:/Users/David/Desktop/db_setup/School_Majors.xlsx', school_majors)
pop.populate()

尝试运行脚本时出现错误消息

Traceback (most recent call last):
  File "populate_school_major.py", line 9, in <module>
    pop = Populator('C:/Users/David/Desktop/db_setup/School_Majors.xlsx', school_majors)
NameError: name 'school_majors' is not defined

但它是有道理的,因为这个脚本在模型部分中查找类名与表的名称,所以我不太确定我将如何填充正确的表,请注意我已经有一个名为majors的表已经使用这个脚本填充了,但是由于django通过一个变量与一个单独的类进行了很多关系,所以我被卡住了。

我尝试使用上面的填充脚本,但注意到这不起作用,因为它正在定位类,而不是数据库表保存为什么。 (在sqlite3中,主题为manytomanyfield的表名称为school_majors)。

如果有人有任何建议我如何填充数据库将是伟大的。

下面是数据库表名称的图片。下面是enter image description here Excel文件

enter image description here

django python-3.x django-models sqlite
2个回答
1
投票

在Django中定义ManyToManyField时,它会在幕后创建一个模型来存储映射。

您可以使用ManyToManyField的through属性访问此模型。在您的情况下,这将是:

locate.models.School.majors.through

您当前的脚本失败,因为school_majors根本不是一个已定义的名称 - 请尝试将其替换为您希望填充的模型的引用:

pop = Populator('C:/Users/David/Desktop/db_setup/School_Majors.xlsx', locate.models.School.majors.through)
pop.populate()

如果这不起作用,您可能希望考虑在ManyToManyField上定义一个显式的through模型(如explained in the Django docs),然后在Populator实例中指定它。

祝好运!


0
投票

不冷不热地说,设置通过允许我创建一个类,我可以用我的脚本引用它,严格地可以通过在model.py中查找类来填充

from django.db import models

class Major(models.Model):
    name = models.CharField(max_length=30, db_index=True)

class School(models.Model):
    name = models.CharField(max_length=50, db_index=True)
    school_Major_merge = models.ManyToManyField(Major, through='School_Major')

class School_Major(models.Model):
    major = models.ForeignKey(Major, on_delete=models.CASCADE)
    school = models.ForeignKey(School, on_delete=models.CASCADE)


class professor(models.Model):
    ProfessorIDS = models.IntegerField()
    ProfessorName = models.CharField(max_length=100)
    ProfessorRating = models.DecimalField(decimal_places=2,max_digits=4)
    NumberofRatings = models.CharField(max_length=50)
    #delete major from the model  
    school = models.ForeignKey(School , on_delete=models.CASCADE)
    major = models.ForeignKey(Major , on_delete=models.CASCADE)

    def __str__(self):
        return self.ProfessorName
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