将参数传递给Scrapy python中的process.crawl

Question

我希望获得与此命令行相同的结果：抓取抓取linkedin_anonymous -a first = James -a last = Bond -o output.json

我的脚本如下：

import scrapy
from linkedin_anonymous_spider import LinkedInAnonymousSpider
from scrapy.crawler import CrawlerProcess
from scrapy.utils.project import get_project_settings

spider = LinkedInAnonymousSpider(None, "James", "Bond")
process = CrawlerProcess(get_project_settings())
process.crawl(spider) ## <-------------- (1)
process.start()

我发现（1）中的process.crawl（）正在创建另一个LinkedInAnonymousSpider，其中first和last为None（在（2）中打印），如果是的话，那么就没有必要创建对象蜘蛛，以及如何创建它可以先将参数最后传递给process.crawl（）吗？

linkedin_anonymous：

from logging import INFO

import scrapy

class LinkedInAnonymousSpider(scrapy.Spider):
    name = "linkedin_anonymous"
    allowed_domains = ["linkedin.com"]
    start_urls = []

    base_url = "https://www.linkedin.com/pub/dir/?first=%s&last=%s&search=Search"

    def __init__(self, input = None, first= None, last=None):
        self.input = input  # source file name
        self.first = first
        self.last = last

    def start_requests(self):
        print self.first ## <------------- (2)
        if self.first and self.last: # taking input from command line parameters
                url = self.base_url % (self.first, self.last)
                yield self.make_requests_from_url(url)

    def parse(self, response): . . .

Answer 1

在process.crawl方法上传递蜘蛛参数：

process.crawl(spider, input='inputargument', first='James', last='Bond')

Answer 2

您可以轻松实现：

from scrapy import cmdline

cmdline.execute("scrapy crawl linkedin_anonymous -a first=James -a last=Bond -o output.json".split())