针对Virtuoso DBPedia的服务给出了“ Virtuoso S0022错误SQ200：无列”

Question

我在一个本地GraphDB三元存储中运行一个SPARQL查询，该查询包含一个转到DBPedia Virtuoso的SERVICE子句。该查询基本上直接从DBPedia获取某些DBPedia URI的标签（请注意，在将这些结果传递给SERVICE子句之前，首先执行该子查询以获取本地结果）：

SELECT DISTINCT ?uri (STR(?theLabel) AS ?label)
WHERE {
 {
  SELECT DISTINCT ?uri 
  WHERE {
    ?domain a <http://xmlns.com/foaf/0.1/Person> .
    ?domain <http://virtual-assembly.org/pair#hasKeyword> ?uri .
  }
  }

  SERVICE <http://dbpedia.org/sparql> {
    ?uri <http://www.w3.org/2000/01/rdf-schema#label> ?theLabel .
    FILTER(lang(?theLabel) = 'fr')
  }

}
ORDER BY ?label

我在评估服务子句时从Virtuoso收到以下错误Virtuoso S0022错误SQ200：

Query evaluation error: org.eclipse.rdf4j.query.QueryEvaluationException: Virtuoso S0022 Error SQ200: No column uri.

SPARQL query:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX sesame: <http://www.openrdf.org/schema/sesame#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
PREFIX fn: <http://www.w3.org/2005/xpath-functions#> 

SELECT  ?theLabel ?__rowIdx WHERE {
 ?uri <http://www.w3.org/2000/01/rdf-schema#label> ?theLabel .
 FILTER(lang(?theLabel) = 'fr')
} 
VALUES (?__rowIdx ?uri) {  ("0" <http://dbpedia.org/resource/Semantic_Web> ) ("1" <http://dbpedia.org/resource/Peer-to-peer> ) ("2" <http://dbpedia.org/resource/Collaboration> ) ("3" <http://dbpedia.org/resource/Free_software> ) ("4" <http://dbpedia.org/resource/Social_transformation> ) ("5" <http://dbpedia.org/resource/Social_network> ) ("6" <http://dbpedia.org/resource/Ecology> ) ("7" <http://dbpedia.org/resource/Activism> ) ("8" <http://dbpedia.org/resource/Supernatural> ) ("9" <http://dbpedia.org/resource/Sociology> ) ("10" <http://dbpedia.org/resource/Natural_science> ) ("11" <http://dbpedia.org/resource/Popular_science> ) ("12" <http://dbpedia.org/resource/Cooperation> ) ("13" <http://dbpedia.org/resource/Wikimedia_Commons> ) ("14" <http://dbpedia.org/resource/Musician> ) } 

(HTTP status 500)

发送到Virtuoso的SP​​ARQL查询在我看来是有效的。

当然，我不熟悉GraphDB如何生成查询，但是有什么办法可以重写原始查询来解决此问题？

谢谢

Answer 1

以下作品，揭示了最初示例的结构性问题。

PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX sesame: <http://www.openrdf.org/schema/sesame#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
PREFIX fn: <http://www.w3.org/2005/xpath-functions#> 

SELECT  ?theLabel ?__rowIdx
WHERE {
       ?uri <http://www.w3.org/2000/01/rdf-schema#label> ?theLabel .
       FILTER(lang(?theLabel) = 'fr')

       VALUES (?__rowIdx ?uri) {  ("0" <http://dbpedia.org/resource/Semantic_Web> ) ("1" <http://dbpedia.org/resource/Peer-to-peer> ) ("2" <http://dbpedia.org/resource/Collaboration> ) ("3" <http://dbpedia.org/resource/Free_software> ) ("4" <http://dbpedia.org/resource/Social_transformation> ) ("5" <http://dbpedia.org/resource/Social_network> ) ("6" <http://dbpedia.org/resource/Ecology> ) ("7" <http://dbpedia.org/resource/Activism> ) ("8" <http://dbpedia.org/resource/Supernatural> ) ("9" <http://dbpedia.org/resource/Sociology> ) ("10" <http://dbpedia.org/resource/Natural_science> ) ("11" <http://dbpedia.org/resource/Popular_science> ) ("12" <http://dbpedia.org/resource/Cooperation> ) ("13" <http://dbpedia.org/resource/Wikimedia_Commons> ) ("14" <http://dbpedia.org/resource/Musician> ) } 

}

Live Query Results page from DBpedia。