如何让catchError返回网络错误？

Question

这曾经工作得很好，但 throwError 已被弃用，现在 catchError 似乎不再返回我以前收到的网络错误。

this.goToApi().subscribe(response => {

  console.log(response);

},
err => {

  console.log(err);

});



public goToApi(): any
{
  return this.apiService.makeApiCall().pipe(map((response: any) => {

    return response;
  }),
    catchError((err) => { console.log(err); return err; })
  )
}

只是补充一下，这个拦截器位于我的 api 服务中，并且它在那里显示错误......

import {
  HttpEvent,
  HttpInterceptor,
  HttpHandler,
  HttpRequest,
  HttpErrorResponse
 } from '@angular/common/http';
 import { Observable, throwError } from 'rxjs';
 import { retry, catchError } from 'rxjs/operators';
 import{ CustomError } from '../../utils/custom-error';
import { Injectable } from "@angular/core";

 @Injectable()
export class HttpErrorInterceptor implements HttpInterceptor {

  intercept(request: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
    return next.handle(request)
      .pipe(
        retry(1),

        catchError((error: HttpErrorResponse) => {
          
          if (!window.navigator.onLine) {

            return throwError(() => new CustomError('Check your internet connection.'));
          }

          return throwError(() => error);
        })
      )
  }

 }

非常感谢您的帮助。

非常感谢

Answer 1

好的，我排序了，返回 throwError(() => error.message);它返回一个对象并寻找一个字符串。