我正在开发一个应用程序,在其中我会创建一个包含已安装应用程序的列表,并让用户选择一个。除了一件事情,我已经一切正常。按字母顺序对其进行排序。这是我正在使用的代码:
private List<App> loadInstalledApps(boolean includeSysApps) {
List<App> apps = new ArrayList<App>();
PackageManager packageManager = getPackageManager();
List<PackageInfo> packs = packageManager.getInstalledPackages(0);
for(int i=0; i < packs.size(); i++) {
PackageInfo p = packs.get(i);
App app = new App();
app.setTitle(p.applicationInfo.loadLabel(packageManager).toString());
app.setPackageName(p.packageName);
app.setVersionName(p.versionName);
app.setVersionCode(p.versionCode);
CharSequence description = p.applicationInfo.loadDescription(packageManager);
app.setDescription(description != null ? description.toString() : "");
apps.add(app);
}
return apps;
}
感谢您的任何帮助!
使用Comparator对数据进行排序...
Collections.sort(apps, new Comparator<App>() {
@Override
public int compare(App lhs, App rhs) {
//here getTitle() method return app name...
return lhs.getTitle().compareTo(rhs.getTitle());
}
});
首先:创建比较器
公共类App实现了Comparable {
// Lista de atributos y métodos
public int compareTo(Object o) {
// logic of comparation
return result; //must be integer
}
}
例如:
public int compareTo(Object o) {
Direccion dir = (Direccion)o;
if(this.name < app.getName())
return -1;
else if(this.name == app.getName())
return 0;
else
return 1;
}
并且当您想短路时,使用Collections.short(list)
最简单的解决方案
Collections.sort(familleList, (famille, t1) -> famille.compareTo(t1));