我想要的形象
我已经尝试过x或y的连接而且它不起作用,即使是小组也没有用。几乎给我结果的是下面的查询
SELECT A.Id ,A.AccNo ,A.Name ,B.Id ,B.AccNo1 ,B.AccNo2 ,B.Name
from Table1 as A
left outer join Table2 as B on A.AccNo = B.AccNo1
union
SELECT A.Id ,A.AccNo ,A.Name ,B.Id, B.AccNo1, B.AccNo2, B.Name,
from Table1 as A
left outer join Table2 as B on A.AccNo = B.AccNo2
在获得正确的查询之后,我想只显示表之间没有链接的异常,如果重复T1.ID则难以实现
你似乎想要一个left join
:
select t1.*, t2.*
from table1 t1 left join
table2 t2
on t1.id in (t2.accno1, t2.accno2);
尝试:
SELECT A.Id ,A.AccNo ,A.Name ,B.Id ,B.AccNo1 ,B.AccNo2 ,B.Name
from Table1 as A
left outer join Table2 as B
ON A.AccNo = (CASE WHEN A.AccNo = B.AccNo1 THEN B.AccNo1 ELSE B.AccNo2 END)
您可以嵌套原始查询,然后使用max aggregate函数进行分组:
SELECT Id ,AccNo ,Name, max(Id2) as Id2, max(Name2) as Name2,
max(AccNo1) as AccNo1, max(AccNo2) as AccNo2
FROM
(
SELECT A.Id ,A.AccNo ,A.Name ,B.Id Id2 ,B.AccNo1 ,B.AccNo2 ,B.Name Name2
from Table1 as A
left outer join Table2 as B on A.AccNo = B.AccNo1
union
SELECT A.Id ,A.AccNo ,A.Name ,B.Id Id2, B.AccNo1, B.AccNo2, B.Name Name2
from Table1 as A
left outer join Table2 as B on A.AccNo = B.AccNo2
) q
GROUP BY Id ,AccNo ,Name;
执行LEFT JOIN
以返回table1值以及匹配的table2值(其中t2.accno2 = t1.accno):
select t1.*, t2.*
from table1 t1
left join table2 t2
on t1.accno = t2.accno2
或者,也许您想要table2值来匹配accno1?
select t1.*, t2.*
from table1 t1
left join table2 t2
on t1.accno in (t2.accno1, t2.accno2)
这样解决:
SELECT
t1.id,
t1.accno,
t1.name,
(
SELECT DISTINCT
id
FROM
table2
WHERE
accno2 = t1.accno
),
(
SELECT DISTINCT
name
FROM
table2
WHERE
accno2 = t1.accno
),
(
SELECT DISTINCT
accno1
FROM
table2
WHERE
accno2 = t1.accno
),
(
SELECT DISTINCT
accno2
FROM
table2
WHERE
accno2 = t1.accno
) FROM
table1 t1
LEFT JOIN table2 t2 ON t1.accno = t2.accno1 OR t1.id = t2.id