Python - 带参数的线程调用脚本

Question

我有一个 python 脚本 script01.py 它需要 4 个参数

我在批处理命令中启动 script01.py，如下所示： python script01.py arg1 arg2 arg3 arg4

现在我想使用 Thread （或任何合适的方法）并行启动 script01.py 并传递参数：

Thread 1 launchs : script01.py A B C D
Thread 2 launchs : script01.py E F G H
Thread 3 launchs : script01.py I J K L
...

我该如何处理这个问题？

谢谢

Answer 1

听起来您需要一个控制函数，然后线程化并启动 script01.py

作为示例，script01 只是一个函数。

import threading
import time


def script01(thread_name, numbers): # Square of numbers
    for number in numbers:
        print(thread_name, number**2)
        time.sleep(1)

def launcher(*args):
    size = len(args)
    group = size // 4
    threads = {}
    for i in range(group):
        threads[i] = threading.Thread(target=script01, args=("thread" + str(i), args[i*4:(i+1)*4]))
    for i in range(group):
        threads[i].start()
    for i in range(group): # Joins the threads to wait for all to be complete before moving on. 
        threads[i].join()

if __name__ == "__main__":
    launcher(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16)

输出如下所示：

thread0 1
thread1 25
thread2 81
thread3 169
thread0 4
thread2 100
thread3 196
thread1 36
thread0 9
thread3 225
thread2 121
thread1 49
thread0 16
thread1 64
thread2 144
thread3 256