我有这样的xml:
<root>
<countries>
<country id="98" nom="Espagne"/>
<country id="76" nom="France"/>
</countries>
</root>
我可以用这个来读取根标记:
Document doc = DocumentBuilderFactory.newInstance()
.newDocumentBuilder().parse(XmlFile);
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
Node NodeCountries = doc.getElementsByTagName("countries").item(0);
System.out.println(nodeToString(NodeCountries));
private static String nodeToString(Node node) throws Exception{
StringWriter sw = new StringWriter();
Transformer t = TransformerFactory.newInstance().newTransformer();
t.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
t.setOutputProperty(OutputKeys.INDENT, "yes");
t.transform(new DOMSource(node), new StreamResult(sw));
return sw.toString();
}
但是我无法获得像这样的国家标签内的所有内容:
<country id="98" nom="Espagne"/>
<country id="76" nom="France"/>
<country id="98" nom="Espagne"/><country id="76" nom="France"/>
:import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.ParserConfigurationException;
import org.xml.sax.InputSource;
import java.io.StringReader;
import org.w3c.dom.Document;
import org.xml.sax.SAXException;
...
String xml = "<root><countries><country id=\"98\" nom=\"Espagne\"/><country id=\"76\" nom=\"France\"/></countries></root>";
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
InputSource is = new InputSource(new StringReader(xml));
Document doc = builder.parse(is);
Node node = doc.getElementsByTagName("countries").item(0);
String innerXml = getInnerXml(node);
System.out.println(innerXml);
并且辅助方法getInnerXml(node)
看起来像这样:
private String getInnerXml(Node node) { DOMImplementationLS lsImpl = (DOMImplementationLS) node.getOwnerDocument().getImplementation().getFeature("LS", "3.0"); LSSerializer lsSerializer = lsImpl.createLSSerializer(); lsSerializer.getDomConfig().setParameter("xml-declaration", false); NodeList childNodes = node.getChildNodes(); StringBuilder sb = new StringBuilder(); for (int i = 0; i < childNodes.getLength(); i++) { sb.append(lsSerializer.writeToString(childNodes.item(i))); } return sb.toString(); }
让我知道我是否误解了要求(再次!)。<< [[[warning]这不是一个很好的解决方案。它涉及“手工”构造XML(即字符串连接),并且如果输入出乎意料的不同或复杂,则会带来结果易碎甚至损坏的风险。