我有疑问,我做错了什么,我的实体显示不像我想要的,当我去h2-console
我可以看到3张桌子,当我去persons
桌子时employee
manager
persons
我看到所有延伸这个abstract
的人上课(employee
,manager
),但是当我去其他桌子时,我只能看到这类课程的id
。我的问题是如何修复它,以及如何使每个表显示从1
盯着的id,因为现在employee表有3个id 1,2,3
,而manager表有4,5
,person表格显示正确。我想在employee表中显示3个雇员,在managers表中显示2个经理,在people表中显示每个实体,并且每个表中的ID都显示为1。
抽象类人
@Entity
@Inheritance(strategy = InheritanceType.JOINED)
@DiscriminatorColumn(name = "descriminatorColumn")
@Table(name = "persons")
public abstract class Person {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private long id;
@Column(name = "first_name")
private String firstName;
@Column(name = "last_name")
private String lastName;
@Column(name = "email")
private String address;
@Column(name = "age")
private int age;
public Person(String firstName, String lastName, String address, int age) {
this.firstName = firstName;
this.lastName = lastName;
this.address = address;
this.age = age;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getAddress() {
return address;
}
public void setAddress(String address) {
this.address = address;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
@Override
public String toString() {
return "Person{" +
"firstName='" + firstName + '\'' +
", lastName='" + lastName + '\'' +
", address='" + address + '\'' +
", age=" + age +
'}';
}
}
Manager类扩展了Person抽象类
@Entity
@Table(name = "managers")
public class Manager extends Person {
public Manager(String firstName, String lastName, String email, int age) {
super(firstName, lastName, email, age);
}
@Override
public String toString() {
return super.toString();
}
}
Employee类扩展了Person抽象类
@Entity
@Table(name = "employees")
public class Employee extends Person {
public Employee(String firstName, String lastName, String address, int age) {
super(firstName, lastName, address, age);
}
@Override
public String toString() {
return super.toString();
}
}
我的问题是如何解决它
绝对没有什么可以解决的,因为使用JOINED继承类型它完全按照您指定的方式执行,即:
https://en.wikibooks.org/wiki/Java_Persistence/Inheritance#Joined,_Multiple_Table_Inheritance
目前,Employee和Manager不定义其他字段,因此这些表中只存在ID。
如果不改变那么你可能最好使用带有鉴别器列的SINGLE_TABLE继承,这样所有数据都将在1个表中。
最后的选择是在数据库级别根本不具有任何继承,即有2个表雇员和经理,它们定义每种类型的所有字段。您可以使用@MappedSuperclass
来执行此操作,这样可以避免在Java类层次结构中复制JPA映射。
https://en.wikibooks.org/wiki/Java_Persistence/Inheritance#Mapped_Superclasses
但要注意这种方法,你无法查询所有人,只能分别为经理和员工查询。