Spring Data MongoDB,按长值搜索

问题描述 投票:0回答:1

我在mongo中存储了一个如下所示的对象(这是我在查看文档时在RoboMongo中的显示方式:]

{
    "_id": ObjectId("5e579c8674f69d1c1451f3ae"),
    ...
    "timestamp": NumberLong(1582800002779),
    ...
    "_class": "regular"
}

我存储的对象是这样定义的:

public class MyObjectModel {
    @Id
    @Field(value = ID_FIELD_NAME)
    private String id;
    @Field(value = TIMESTAMP_FIELD_NAME)
    private Long timestamp;
...
}

我的意图是获取时间范围内的对象列表。这就是我用spring数据mongo db创建查询的方式:

    public List<Criteria> generateAllCriteria() {
        List<Criteria> criteriaList = new ArrayList<>();
        Optional.ofNullable(searchCriteria.getFromTimestamp()).map(ts -> criteriaList.add(generateFromTimestampCriteria(ts)));
        Optional.ofNullable(searchCriteria.getToTimestamp()).map(ts -> criteriaList.add(generateToTimestampCriteria(ts)));
        return criteriaList;
    }

    private Criteria generateFromTimestampCriteria(Long fromTimestamp) {
        Criteria critFromTimestamp = Criteria.where(TIMESTAMP_FIELD_NAME).gte(fromTimestamp);
        log.debug("From Timestamp criteria {}", critFromTimestamp.getCriteriaObject().toJson());
        return critFromTimestamp;
    }

    private Criteria generateToTimestampCriteria(Long toTimestamp) {
        Criteria critToTimestamp = Criteria.where(TIMESTAMP_FIELD_NAME).lt(toTimestamp);
        log.debug("To Timestamp criteria {}", critToTimestamp.getCriteriaObject().toJson());
        return critToTimestamp;
    }
...
    List<Criteria> criteriaList = generateAllCriteria();

    Criteria finalCriteria = new Criteria();
    finalCriteria = finalCriteria.andOperator(criteriaList.toArray(new Criteria[criteriaList.size()]));
    log.debug("Final criteria {}", finalCriteria);
    Query query = new Query();
    query.addCriteria(finalCriteria);

    List<MyObjectModel> myObjects = mongoTemplate.find(query, MyObjectModel.class);

当我显示查询时,它们是以下内容:

From Timestamp criteria { "timestamp" : { "$gte" : { "$numberLong" : "1582714365857" } } }
To Timestamp criteria { "timestamp" : { "$lt" : { "$numberLong" : "1582887165858" } } }

最终的查询条件似乎是这样:

o.s.data.mongodb.core.MongoTemplate - find using query: { "$and" : [{ "timestamp" : { "$gte" : { "$numberLong" : "1582714365857" } } }, { "timestamp" : { "$lt" : { "$numberLong" : "1582887165858" } } }] } fields: Document{{}} for class: class mypackage.model.MyObjectModel in collection: myObjectModel

乍看之下似乎还可以,但是当我手动对Mongo运行它时,它不会返回任何记录,我认为这是不正确的。这正是我在Mongo上运行的内容:

db.getCollection('my-collection').find({ "$and" : [{ "timestamp" : { "$gte" : { "$numberLong" : "1582707873806" } } }, { "timestamp" : { "$lt" : { "$numberLong" : "1582887165858" } } }] })

并且它显然不返回任何记录。但是,当我修改查询并摆脱$ numberLong:

db.getCollection('my-collection').find({ "$and" : [{ "timestamp" : { "$gte" : 1582707873806 } }, { "timestamp" : { "$lt" : 1582887165858 } }] })

它像一种魅力。

有人可以启发我并解释我做错了什么吗?应该如何以正确的方式完成?如何使spring数据mongo创建适当的查询?

不用说,字符串和整数工作正常。仅约LONG s。

提前感谢您的帮助。

java spring mongodb spring-data-mongodb
1个回答
0
投票

据我了解:

  • 从/到是查询中的唯一参数
  • 都可以为null

并且假设您的模型是:

public class Regular {
  @Id
  private String id;

  @Field
  private Long timestamp;
}

然后可能的解决方案(恕我直言,简短得多)是:

// exists(true) is a "hack" to return the elements in case both from/to are null
public List<Regular> find(Long from, Long to) {

  var criteria = where("timestamp").exists(true);
  if(from != null) {
    criteria.gte(from);
  }
  if(to != null) {
    criteria.lte(to);
  }

  return mongoTemplate.find(Query.query(criteria), Regular.class);
}

PS。我已经用Spring Boot 2.2.4Mongo 3.6检查了它。

PS2。仍然可以通过额外的if条件处理from / to均为null的情况,然后删除exists(true)

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