Python中小float值的二进制表示形式

Question

如何将较小的浮点值（例如1.942890293094024e-15或2.8665157186802404e-07转换为Python中的二进制值？

我尝试过GeeksforGeek's solution，但是对于如此小的值不起作用（我收到此错误：ValueError：int（）的无效文字，基数为10：'1.942890293094024e-15'。

]

到目前为止，代码看起来像这样：

def float_bin(number, places = 3): 

    # split() seperates whole number and decimal  
    # part and stores it in two seperate variables 
    whole, dec = str(number).split(".") 

    # Convert both whole number and decimal   
    # part from string type to integer type 
    whole = int(whole) 
    dec = int (dec) 

    # Convert the whole number part to it's 
    # respective binary form and remove the 
    # "0b" from it. 
    res = bin(whole).lstrip("0b") + "."

    # Iterate the number of times, we want 
    # the number of decimal places to be 
    for x in range(places): 

        # Multiply the decimal value by 2  
        # and seperate the whole number part 
        # and decimal part 
        whole, dec = str((decimal_converter(dec)) * 2).split(".") 

        # Convert the decimal part 
        # to integer again 
        dec = int(dec) 

        # Keep adding the integer parts  
        # receive to the result variable 
        res += whole 

    return res 


# Function converts the value passed as 
# parameter to it's decimal representation 
def decimal_converter(num):  
  while num > 1: 
      num /= 10
  return num 

Answer 1

经过一番咨询，我找到了可以解决我问题的好piece of code。我只需要对其进行一些调整（使其成为功能，删除自动输入请求等）。

非常感谢@kartoon！

Answer 2

我看到的一个问题是str(number).split(".")。在此之前，我添加了一个简单的技巧：number = "{:30f}".format(number)，因此没有e的数量。不过，我不确定结果是否正确。