我正在尝试构建DSL,此DSL上的一种方法是无参数的,并使用有界的泛型类型。今天,我必须添加一个“功能”,理想情况下将使用相同的方法名称。但是,因为唯一的参数是通用参数,所以我无法用通常的方法覆盖它。
是否有技巧允许对不同的泛型使用相同的方法?
我的方法如下:
def ask[H <: Handler] = {
new CommandBuilder[H]
}
class CommandBuilder[H <: Handler] {
def toExecute[C <: H#C](command: C) = {
//...
}
}
而且我想补充:
def ask[S <: State] = {
new QueryBuilder[S]
}
class QueryBuilder[S <: State] {
def toExecute[Q <: S#Q](query: Q) = {
//...
}
}
我曾想过在类型上匹配ClassTag
的类型,但我需要强大的类型安全性:
Query
上的[Handler
]是不允许的。 ask [State]必须返回QueryBuilderCommand
和Query
是唯一受支持的类型。 ask
的通用类型只能是Handler
或State
。也许您可以将代码重构为这样的内容?
sealed trait FooBar
sealed trait Foo extends FooBar {
def process(i: Int): Int
}
object Foo {
implicit final case object FooImpl extends Foo {
override def process(i: Int): Int = i + 1
}
}
sealed trait Bar extends FooBar {
def process(s: String): String
}
object Bar {
implicit final case object BarImpl extends Bar {
override def process(s: String): String = s.toUpperCase
}
}
object Test {
trait FooBarPartiallyApplied[FB <: FooBar] {
type Out
val out: Out
}
object FooBarPartiallyApplied {
type Aux[FB <: FooBar, _Out] = FooBarPartiallyApplied[FB] { type Out = _Out }
implicit final def FooPartiallyAppliedBuilder[F <: Foo]: Aux[F, FooPartiallyApplied[F]] =
new FooBarPartiallyApplied[F] {
override final type Out = FooPartiallyApplied[F]
override final val out: FooPartiallyApplied[F] =
new FooPartiallyApplied[F](dummy = true)
}
implicit final def BarPartiallyAppliedBuilder[B <: Bar]: Aux[B, BarPartiallyApplied[B]] =
new FooBarPartiallyApplied[B] {
override final type Out = BarPartiallyApplied[B]
override final val out: BarPartiallyApplied[B] =
new BarPartiallyApplied[B](dummy = true)
}
final class FooPartiallyApplied[F <: Foo](private val dummy: Boolean) extends AnyVal {
def toExecute(i: Int)(implicit foo: F): Int = foo.process(i)
}
final class BarPartiallyApplied[B <: Bar](private val dummy: Boolean) extends AnyVal {
def toExecute(s: String)(implicit bar: B): String = bar.process(s)
}
}
def ask[FB <: FooBar](implicit pa: FooBarPartiallyApplied[FB]): pa.Out =
pa.out
}
它按预期工作:
Test.ask[Foo.FooImpl.type].toExecute(10)
// res: Int = 11
Test.ask[Foo.FooImpl.type].toExecute("blah")
// Type error.
Test.ask[Bar.BarImpl.type].toExecute(10)
// Type error.
Test.ask[Bar.BarImpl.type].toExecute("blah")
// res: String = "BLAH"