我正在做沙沙声练习,在完成其中一项练习后我得到了一个简单的问题,但我也不确定我没有做错其他事情。
问题是:Rust 是否支持用方括号进行索引以返回可变的内容,但
HashMap<K, V>
没有实现它?如果不是这样,我做错了什么?
以下是整个练习供参考:
fn build_scores_table(results: String) -> HashMap<String, Team> {
// The name of the team is the key and its associated struct is the value.
let mut scores: HashMap<String, Team> = HashMap::new();
for r in results.lines() {
let v: Vec<&str> = r.split(',').collect();
let team_1_name = v[0].to_string();
let team_1_score: u8 = v[2].parse().unwrap();
let team_2_name = v[1].to_string();
let team_2_score: u8 = v[3].parse().unwrap();
// TODO: Populate the scores table with details extracted from the
// current line. Keep in mind that goals scored by team_1
// will be the number of goals conceded from team_2, and similarly
// goals scored by team_2 will be the number of goals conceded by
// team_1.
}
scores
}
我尝试了几种不同的方法,找到了一种可以编译的方法。这对我来说感觉有点奇怪,但我认为这是一个好兆头因为我是生锈新手,而且因为它看起来干净,即使它对我来说感觉不传统。
let team1 = scores.get_mut(&team_1_name);
match team1 {
Some(t) => {
t.goals_scored += team_1_score;
t.goals_conceded += team_2_score;
},
None => {
scores.insert(team_1_name, Team {
goals_scored: team_1_score,
goals_conceded: team_2_score
});
}
}
但是,这不能编译。答案可能是方括号表示法,它似乎是
index
的语法糖,不会返回可变的,但我想检查这是否正确。
if ! scores.contains_key(&team_2_name) {
scores.insert(team_2_name.clone(), Team { goals_conceded: 0, goals_scored: 0 });
}
let team2 = scores[&team_2_name];
team2.goals_scored += team_2_score;
team2.goals_conceded += team_1_score;
我试图让编译器来教我。我知道
let team2...
行是错误的,因为它不是可变的,但我认为编译器可能会给我一个很好的提示。
error[E0594]: cannot assign to `team2.goals_scored`, as `team2` is not declared as mutable
--> exercises/hashmaps/hashmaps3.rs:62:9
|
62 | team2.goals_scored += team_2_score;
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ cannot assign
|
help: consider changing this to be mutable
|
61 | let mut team2 = scores[&team_2_name];
| +++
这让我很感动:
error[E0507]: cannot move out of index of `HashMap<String, Team>`
--> exercises/hashmaps/hashmaps3.rs:61:25
|
61 | let mut team2 = scores[&team_2_name];
| ^^^^^^^^^^^^^^^^^^^^ move occurs because value has type `Team`, which does not implement the `Copy` trait
|
help: consider borrowing here
|
61 | let mut team2 = &scores[&team_2_name];
| +
然后我得到:
warning: variable does not need to be mutable
--> exercises/hashmaps/hashmaps3.rs:61:13
|
61 | let mut team2 = &scores[&team_2_name];
| ----^^^^^
| |
| help: remove this `mut`
|
= note: `#[warn(unused_mut)]` on by default
error[E0594]: cannot assign to `team2.goals_scored`, which is behind a `&` reference
--> exercises/hashmaps/hashmaps3.rs:62:9
|
62 | team2.goals_scored += team_2_score;
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ `team2` is a `&` reference, so the data it refers to cannot be written
接下来是:
error[E0594]: cannot assign to `team2.goals_scored`, which is behind a `&` reference
--> exercises/hashmaps/hashmaps3.rs:62:9
|
62 | team2.goals_scored += team_2_score;
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ `team2` is a `&` reference, so the data it refers to cannot be written
|
help: consider changing this to be a mutable reference
|
61 | let team2 = &mut scores[&team_2_name];
| +++
error[E0594]: cannot assign to `team2.goals_conceded`, which is behind a `&` reference
--> exercises/hashmaps/hashmaps3.rs:63:9
|
63 | team2.goals_conceded += team_1_score;
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ `team2` is a `&` reference, so the data it refers to cannot be written
|
help: consider changing this to be a mutable reference
|
61 | let team2 = &mut scores[&team_2_name];
| +++
最后,我得到:
error[E0596]: cannot borrow data in an index of `HashMap<String, Team>` as mutable
--> exercises/hashmaps/hashmaps3.rs:61:21
|
61 | let team2 = &mut scores[&team_2_name];
| ^^^^^^^^^^^^^^^^^^^^^^^^^ cannot borrow as mutable
|
= help: trait `IndexMut` is required to modify indexed content, but it is not implemented for `HashMap<String, Team>`
= help: to modify a `HashMap<String, Team>`, use `.get_mut()`, `.insert()` or the entry API
有趣的是,我认为它建议做与我为第一个解决方案所做的类似的事情。