我认识我，我的问题听起来很愚蠢，因为网上有很多答案。我已经创建了一个用于登录和注册的html页面。我被要求使用xampp来托管我的网页。我创建了一个数据库和表，并在xampp的sql中插入数据。但是当我提供lognin和注册详细信息并提交时，该页面会抛出各种异常。我在这里发布这个的主要原因是，这是我的最终项目在3天内有截止日期，如果我甚至不做这个简单的工作，我就不会被评分。我尝试了很多，但我一直在收到错误。所以我需要一些快速的帮助。我需要一个使用连接到数据库的php登录页面。你的一点帮助可以让我免于得到F，我真的很感激。
数据库结构
CREATE TABLE IF NOT EXISTS `users` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`username` varchar(255) NOT NULL,
`password` varchar(255) NOT NULL,
`first_name` varchar(255) NOT NULL,
`last_name` varchar(255) NOT NULL,
`email` varchar(255) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `username` (`username`),
UNIQUE KEY `email` (`email`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
如果你使用mysql使用phpmyadmin创建这些字段会更容易
现在我已经定义了连接到数据库所需的常量创建一个文件dbConstants.php或者命名它，无论你想要什么
现在，登录页面的代码创建了一个名为register.php的文件
<html>
<head>
<title>Login Form</title>
</head>
<body>
<?php
if (!isset($_POST['submit'])){
?>
<!-- The HTML login form -->
<form action="<?=$_SERVER['PHP_SELF']?>" method="post">
Username: <input type="text" name="username" /><br />
Password: <input type="password" name="password" /><br />
<input type="submit" name="submit" value="Login" />
</form>
<?php
} else {
require_once("db_const.php");
$mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);
# check connection
if ($mysqli->connect_errno) {
echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli->connect_error}</p>";
exit();
}
$username = $_POST['username'];
$password = $_POST['password'];
$sql = "SELECT * from users WHERE username LIKE '{$username}' AND password LIKE '{$password}' LIMIT 1";
$result = $mysqli->query($sql);
if (!$result->num_rows == 1) {
echo "<p>Invalid username/password combination</p>";
} else {
echo "<p>Logged in successfully</p>";
// do stuffs
}
}
?>
</body>
</html>
最后，注册代码创建了一个名为register.php的文件
<html>
<head>
<title>Registration</title>
</head>
<body>
<?php
require_once("db_const.php");
if (!isset($_POST['submit'])) {
?> <!-- The HTML registration form -->
<form action="<?=$_SERVER['PHP_SELF']?>" method="post">
Username: <input type="text" name="username" /><br />
Password: <input type="password" name="password" /><br />
First name: <input type="text" name="first_name" /><br />
Last name: <input type="text" name="last_name" /><br />
Email: <input type="type" name="email" /><br />
<input type="submit" name="submit" value="Register" />
</form>
<?php
} else {
## connect mysql server
$mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);
# check connection
if ($mysqli->connect_errno) {
echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli->connect_error}</p>";
exit();
}
## query database
# prepare data for insertion
$username = $_POST['username'];
$password = $_POST['password'];
$first_name = $_POST['first_name'];
$last_name = $_POST['last_name'];
$email = $_POST['email'];
# check if username and email exist else insert
$exists = 0;
$result = $mysqli->query("SELECT username from users WHERE username = '{$username}' LIMIT 1");
if ($result->num_rows == 1) {
$exists = 1;
$result = $mysqli->query("SELECT email from users WHERE email = '{$email}' LIMIT 1");
if ($result->num_rows == 1) $exists = 2;
} else {
$result = $mysqli->query("SELECT email from users WHERE email = '{$email}' LIMIT 1");
if ($result->num_rows == 1) $exists = 3;
}
if ($exists == 1) echo "<p>Username already exists!</p>";
else if ($exists == 2) echo "<p>Username and Email already exists!</p>";
else if ($exists == 3) echo "<p>Email already exists!</p>";
else {
# insert data into mysql database
$sql = "INSERT INTO `users` (`id`, `username`, `password`, `first_name`, `last_name`, `email`)
VALUES (NULL, '{$username}', '{$password}', '{$first_name}', '{$last_name}', '{$email}')";
if ($mysqli->query($sql)) {
//echo "New Record has id ".$mysqli->insert_id;
echo "<p>Registred successfully!</p>";
} else {
echo "<p>MySQL error no {$mysqli->errno} : {$mysqli->error}</p>";
exit();
}
}
}
?>
</body>
</html>
这是一个简单的登录和注册过程我希望它可以帮助你，虽然我在这里给出的东西可能不是最佳实践，至少会帮助你使用mysqli更好地使用pdo。