无法在React App中输入字段

问题描述 投票:0回答:2

[每当我尝试启动该应用程序时,我都无法在输入字段中编写任何内容。也许是因为react正在重新渲染某些组件,因为我每次点击都会调用setState。

父App.js包含具有输入字段的SearchForm。每当在输入字段中输入数据时,我都会调用处理程序来设置状态,以便在按钮上单击可对API进行提取

这是我的app.js文件。

import React from 'react';
import { BrowserRouter, Route, Switch } from 'react-router-dom';
import './App.css';
import NavigationBar from './components/NavigationBar/NavigationBar.js';
import Logo from './components/Logo/Logo.js';
import SearchForm from './components/SearchForm/SearchForm.js';
import SearchFilter from './components/SearchFilter/SearchFilter.js';
import ReviewComponent from './components/ReviewComponent/ReviewComponent.js';


class App extends React.Component {
  constructor(){
    super();
    this.state = {
      searchfield: '', 
      searchresults: {}
    }
    this.onInputChange = this.onInputChange.bind(this);
    this.onSearchClick = this.onSearchClick.bind(this);
  }

  onInputChange = (event) => {
    this.setState({searchfield: event.target.value});
  }

  onSearchClick = () => {
    fetch('https://maps.googleapis.com/maps/api/place/findplacefromtext/json?key=&inputtype=textquery&type=restaurant&input=kfc&fields=name,place_id,formatted_address')
      .then(response=> response.json())
      .then(results => {this.setState({ searchresults: results})})
      .then(results => {console.log("lulli" + JSON.stringify(this.state.searchresults))});
  }

  render(){
    return (
      <div className="App">
        <BrowserRouter> {/* using react-router-dom for routing */}
          <NavigationBar />  {/* for navigation through the app, always rendered */}
          <Logo />   {/* a logo for the RestrauntReviewsTool */}
          <Switch>
            <Route path='/' 
              exact 
              component={() => <SearchForm onInputChange={this.onInputChange} onSearchClick={this.onSearchClick} /> } 
            />  
            <Route 
              path='/searchfilter' 
              component={() => <SearchFilter searchresults={this.searchresults} /> } 
            />  

            <ReviewComponent path='/reviewcomponent' component={ReviewComponent} /> {/* final restaurant details */}
          </Switch>
        </BrowserRouter>

      </div>
    );
  }
}


export default App;

这是我的SearchForm.js

import React from 'react';
import {Link} from 'react-router-dom';

const SearchForm = ({ onInputChange, onSearchClick }) => {
    return(
        <div>
            <p className='f3'>
                {'Search here for restaurants, maybe make an api fetch here and populate data in the SearchFilter component'}
            </p>
            <div className='center'>
                <div className='form center pa4 br3 shadow-5'>
                    <input className='f4 pa2 w-70 center' type='text' onChange={onInputChange}/>
                    <button className='w-30 grow f4 ph3 pv2 dib white bg-light-purple' onClick={onSearchClick}>
                    <Link to ='/searchfilter'>
                    Search   
                    </Link>    
                    </button>

                </div>
            </div>
        </div>
    );
}

export default SearchForm;
javascript reactjs react-router google-places-api
2个回答
0
投票

您需要将searchField状态作为道具传递给Child组件。

在SearchForm组件内部,您的输入需要具有value = {searchField}

因此,当您的searchField状态更改时,子组件将重新呈现。

class App extends React.Component {
  constructor(){
    super();
    this.state = {
      searchfield: '', 
      searchresults: {}
    }
    this.onInputChange = this.onInputChange.bind(this);
    this.onSearchClick = this.onSearchClick.bind(this);
  }

  onInputChange = (event) => {
    this.setState({searchfield: event.target.value});
  }

  onSearchClick = () => {
    fetch('https://maps.googleapis.com/maps/api/place/findplacefromtext/json?key=&inputtype=textquery&type=restaurant&input=kfc&fields=name,place_id,formatted_address')
      .then(response=> response.json())
      .then(results => {this.setState({ searchresults: results})})
      .then(results => {console.log("lulli" + JSON.stringify(this.state.searchresults))});
  }

  render(){
    return (
      <div className="App">
        <BrowserRouter> {/* using react-router-dom for routing */}
          <NavigationBar />  {/* for navigation through the app, always rendered */}
          <Logo />   {/* a logo for the RestrauntReviewsTool */}
          <Switch>
            <Route path='/' 
              exact 
              component={() => <SearchForm searchfield={this.state.searchfield} onInputChange={this.onInputChange} onSearchClick={this.onSearchClick} /> } 
            />  
            <Route 
              path='/searchfilter' 
              component={() => <SearchFilter searchresults={this.searchresults} /> } 
            />  

            <ReviewComponent path='/reviewcomponent' component={ReviewComponent} /> {/* final restaurant details */}
          </Switch>
        </BrowserRouter>

      </div>
    );
  }
}


export default App;

import React from 'react';
import {Link} from 'react-router-dom';

const SearchForm = ({ searchField, onInputChange, onSearchClick }) => {
    return(
        <div>
            <p className='f3'>
                {'Search here for restaurants, maybe make an api fetch here and populate data in the SearchFilter component'}
            </p>
            <div className='center'>
                <div className='form center pa4 br3 shadow-5'>
                    <input className='f4 pa2 w-70 center' type='text' value={searchField} onChange={onInputChange}/>
                    <button className='w-30 grow f4 ph3 pv2 dib white bg-light-purple' onClick={onSearchClick}>
                    <Link to ='/searchfilter'>
                    Search   
                    </Link>    
                    </button>

                </div>
            </div>
        </div>
    );
}

export default SearchForm;

0
投票

实际上,在ReactJS中,开发人员另外对input的控制更改也应控制input的值:

handleInputChangeValue = e =>
  this.setState({
    inputValue: e.target.value
  });

~~~

<input
  type="text"
  value={this.state.inputValue}
  onChange={this.handleInputChangeValue}
/>

但是,在您的代码上,您只是处理了更改,并且没有将新值传递给input标记:

<input className='f4 pa2 w-70 center' type='text' onChange={onInputChange}/>
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