我试图列出我们网络中的所有用户别名。但是,我遇到了一些麻烦。我在这里使用一些固定代码。我知道别名是一个数组,但每个用户访问它然后只列出别名让我看到双倍。任何帮助或提示非常感谢!
function AliasDomainUsersList() {
var users_alias = [];
var options_alias = {
domain: "northstarmoving.com", // Google Apps domain name
customer: "my_customer",
maxResults: 100,
projection: "full", // Fetch basic details of users
viewType: "domain_public",
orderBy: "email" // Sort results by users
}
do {
var response = AdminDirectory.Users.list(options_alias);
response.users.forEach(function(user) {
users_alias.push([user.name.fullName, user.primaryEmail]);
});
// For domains with many users, the results are paged
if (response.nextPageToken) {
options_alias.pageToken = response.nextPageToken;
}
} while (response.nextPageToken);
// Insert data in a spreadsheet
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("Users-Aliases") || ss.insertSheet("Users-Aliases", 1);
sheet.getRange(1,1,users_alias.length, users_alias[0].length).setValues(users_alias);
}
我觉得这样的事情可能有用。我没有测试过这个,因为我是我企业帐户中唯一的人。
function AliasDomainUsersList() {
var users_alias = [];
var options_alias = {
domain: "northstarmoving.com", // Google Apps domain name
customer: "my_customer",
maxResults: 100,
projection: "full", // Fetch basic details of users
viewType: "domain_public",
orderBy: "email" // Sort results by users
}
do {
var response = AdminDirectory.Users.list(options_alias);
for(var i=0;i<response.users.length;i++) {//you will probably want to do this your way.
users_alias.push([response.users[i].name,response.users[i].primaryEmail]);
}
// For domains with many users, the results are paged
if (response.nextPageToken) {
options_alias.pageToken = response.nextPageToken;
}
} while (response.nextPageToken);
// Insert data in a spreadsheet
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("Users-Aliases") || ss.insertSheet("Users-Aliases", 1);
sheet.getRange(1,1,users_alias.length, users_alias[0].length).setValues(users_alias);
var sheet2=ss.getSheetByName('AnotherSheet')
var rg2=sheet2.getRange(1,1,users_alias.length,1);
var vA2=rg2.getValues();
for(var i=0;i<vA2.length;i++) {
vA2[i][0]=users_alias[i][1];
}
rg2.setValues(vA2);
}
管理解决方案(有一些帮助)。这里是:
function getDomainUsersList() {
var users = [];
var options = {
domain: "northstarmoving.com", // Google Apps domain name
customer: "my_customer",
maxResults: 500,
projection: "full", // Fetch details of users
viewType: "domain_public",
orderBy: "email" // Sort results by users
}
do {
var response = AdminDirectory.Users.list(options);
response.users.forEach(function(user) {
users.push([user.name.fullName, user.primaryEmail]);
});
// For domains with many users, the results are paged
if (response.nextPageToken) {
options.pageToken = response.nextPageToken;
}
} while (response.nextPageToken);
// Insert data in a spreadsheet
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("Users") || ss.insertSheet("Users", 1);
sheet.getRange(1,1,users.length, users[0].length).setValues(users);
}