如何防止自定义DialogFragment在显示时隐藏键盘

Question

有两种方法可以通过DialogFragment创建自定义对话框。

1. 覆盖onCreateDialog并使用AlertDialog.Builder返回一个对话框。
2. 覆盖onCreateView。

我们注意到，如果我们覆盖onCreateDialog，之前显示的软键盘将不会被隐藏。

但是，如果我们覆盖onCreateView，之前显示的软键盘将被隐藏。

onCreateDialog不会隐藏软键盘

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onCreateView将隐藏软键盘

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隐藏软键盘不是我们想要的行为。我们希望软键盘保持原样。

但是，由于onCreateDialog提到的限制，我们无法使用ViewPager in DialogFragment - IllegalStateException: Fragment does not have a view方式。简而言之，如果您需要ViewPager在对话框中正常工作，则无法使用onCreateDialog实现自定义对话框。

如果我们使用onCreateView，我们可以实现所需的一切，除了“不隐藏软键盘”。

你知道为什么要覆盖onCreateView创建自定义对话框，会隐藏键盘吗？我们怎样才能防止这种行为呢？

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码

我的对话框样式是：

<style name="CustomDialog" parent="@style/Theme.AppCompat.Light.Dialog">
    <item name="android:windowNoTitle">false</item>
</style>

color dialog fragment.Java:

public class ColorDialogFragment extends DialogFragment {
    private TabLayout tabLayout;
    private ViewPager viewPager;
    private ColorFragmentPagerAdapter colorFragmentPagerAdapter;

    public static ColorDialogFragment newInstance() {
        ColorDialogFragment colorDialogFragment = new ColorDialogFragment();
        // We provide custom style, because we need title.
        colorDialogFragment.setStyle(DialogFragment.STYLE_NORMAL, R.style.CustomDialog);
        return colorDialogFragment;
    }

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
    }

    @Override
    public void onResume() {
        super.onResume();
        getDialog().getWindow().setLayout(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT);
    }

    private View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container) {
        View view = inflater.inflate(R.layout.color_dialog_fragment, container, false);

        this.tabLayout = view.findViewById(R.id.tab_layout);
        this.viewPager = view.findViewById(R.id.view_pager);
        this.colorFragmentPagerAdapter = new ColorFragmentPagerAdapter(this.getChildFragmentManager());
        this.viewPager.setAdapter(this.colorFragmentPagerAdapter);
        this.tabLayout.setupWithViewPager(this.viewPager);

        return view;
    }

    // We overwrite onCreateView because ViewPager in DialogFragment, can hardly play well with
    // onCreateDialog + AlertDialog.Builder.
    //
    // https://stackoverflow.com/questions/20303865/viewpager-in-dialogfragment-illegalstateexception-fragment-does-not-have-a-vi
    @Override
    public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
        return onCreateView(inflater, container);
    }

    // We overwrite onCreateDialog, because we need title.
    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState) {
        Dialog dialog = super.onCreateDialog(savedInstanceState);
        dialog.setTitle(R.string.select_a_color);
        return dialog;
    }
}

Answer 1

经过一天的实验，我找到了解决方案！

覆盖onCreateDialog和onCreateView。将onCreateDialog中创建的视图存储在成员变量中，让onCreateView返回该成员变量。

参考：https://stackoverflow.com/a/51530917/72437

这是完整的代码。

public class ColorDialogFragment extends DialogFragment {
    private View view;
    private TabLayout tabLayout;
    private ViewPager viewPager;
    private ColorFragmentPagerAdapter colorFragmentPagerAdapter;

    public static ColorDialogFragment newInstance() {
        ColorDialogFragment colorDialogFragment = new ColorDialogFragment();
        return colorDialogFragment;
    }

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
    }

    @Override
    public void onResume() {
        super.onResume();
        getDialog().getWindow().setLayout(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT);


        // TODO: Read from WeNoteOptions.
        final int position = 0;
        this.viewPager.setCurrentItem(position);
        updateButtonVisibility(position);
    }

    private View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container) {
        View view = inflater.inflate(R.layout.color_dialog_fragment, container, false);

        this.tabLayout = view.findViewById(R.id.tab_layout);
        this.viewPager = view.findViewById(R.id.view_pager);
        this.colorFragmentPagerAdapter = new ColorFragmentPagerAdapter(this.getChildFragmentManager());
        this.viewPager.setAdapter(this.colorFragmentPagerAdapter);
        this.tabLayout.setupWithViewPager(this.viewPager);

        this.viewPager.addOnPageChangeListener(new ViewPager.OnPageChangeListener() {
            @Override
            public void onPageScrolled(int position, float positionOffset, int positionOffsetPixels) {

            }

            @Override
            public void onPageSelected(int position) {
                updateButtonVisibility(position);
            }

            @Override
            public void onPageScrollStateChanged(int state) {

            }
        });

        return view;
    }

    private void updateButtonVisibility(int position) {
        if (position == 1) {
            ((AlertDialog)getDialog()).getButton(DialogInterface.BUTTON_POSITIVE).setVisibility(View.VISIBLE);
        } else {
            ((AlertDialog)getDialog()).getButton(DialogInterface.BUTTON_POSITIVE).setVisibility(View.INVISIBLE);
        }
    }

    // https://stackoverflow.com/questions/20303865/viewpager-in-dialogfragment-illegalstateexception-fragment-does-not-have-a-vi
    @Override
    public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
        return this.view;
    }

    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState) {
        LayoutInflater layoutInflater = getActivity().getLayoutInflater();
        this.view = onCreateView(layoutInflater, null);
        AlertDialog.Builder alertDialogBuilder = new AlertDialog.Builder(getActivity())
                .setTitle(R.string.select_a_color)
                .setView(this.view)
                .setPositiveButton(R.string.select_color, (dialogInterface, i) -> {

                });
        return alertDialogBuilder.create();
    }
}