有关Hana Studio(SQL脚本)触发器的条件更新

问题描述 投票:0回答:2

我有两个示例表:

    TABLE1:
      ID    | COLUMN_B| COLUMN_C
   _________|_________|_________
       1    |    0    |    1
    ________|_________|_________
       2    |    0    |    1
    ________|_________|_________
       3    |    0    |    1


    TABLE2:
      ID    | COLUMN_E| COLUMN_F
    ________|_________|________
       1    |    Y    |    X
    ________|_________|_________
       2    |    Y    |    X
    ________|_________|_________
       3    |    Y    |    X

我想要做的是使用SQL脚本在Hana Studio上编写一个触发器,以便在表1中的B列更新为特定值(比如100)时更新表2中的E列。表1中的行与第一列(ID)一起引用。

我写了以下代码:

create trigger "UPDATE_TABLES"
    after update of "COLUMN_B" on "TABLE1"
    referencing new row as new, old row as old
    for each row 
begin
    update "TABLE2"
    set "COLUMN_E" = 'my new value'
    where :old."COLUMN_B" = '100' and "TABLE1"."ID" = :old."ID";
end;

当我将第1行上的TABLE1.COLUMN_B设置为100时,我希望代码在第1行将TABLE2.COLUMN_E更改为“我的新值”,但没有任何反应。任何人都可以指出我在这里做错了什么?

sap hana sql-scripts hana-sql-script hana-studio
2个回答
1
投票

我想触发器代码中的UPDATE语句应该略有不同,如下所示

create trigger "UPDATE_TABLES"
    after update of "COLUMN_B" on "TABLE1"
    referencing new row as new, old row as old
    for each row 
begin
    update "TABLE2"
    set "COLUMN_E" = 'my new value'
    where :new."COLUMN_B" = '100' 
    and TABLE2.ID = :old."ID";
end;

否则,我在创建触发器时会出现语法错误您可以验证吗?


0
投票

菜鸟错了。我希望column_e值在column_b的值更改时更改,但我实际上是在跟踪column_b中的旧值。更正为:

create trigger "UPDATE_TABLES"
    after update of "COLUMN_B" on "TABLE1"
    referencing new row as new, old row as old
    for each row 
begin
    update "TABLE2"
    set "COLUMN_E" = 'my new value'
    where :new."COLUMN_B" = '100' and "TABLE1"."ID" = :old."ID";
end;

它工作了!

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