我想在跨度 ID 中多次使用随机数结果 但即使克隆或委托结果也只会在结果中出现一次,而其他结果则显示为空白
我不知道该怎么做,它可以帮助我吗?
javascript
var min = 50;
var max = 150;
var play1;
var play2;
window.onload = function() {
play1 = Math.floor(Math.random() * (max - min + 1)) + min;
max = 10 - play1
document.getElementById("yourNumber").innerHTML = play1;
if (play1 < 10 ) {
play2 = Math.floor(Math.random()*(max-min+1)) + min;
} else {
play2 = Math.floor(Math.random() * 10) + 1;
}
document.getElementById("yourNumber1").innerHTML = play2;
}
HTML
(<span id="yourNumber"></span> user log)
(<span id="yourNumber1"></span> users logs)
(<span id="yourNumber1"></span> users logs)
(<span id="yourNumber1"></span> users logs)
(<span id="yourNumber1"></span> users logs)
谢谢你!
尝试克隆并委托随机数
需要用不同的数字显示其他四个结果
将 id 替换为 class,因为它是唯一值
身体
<span id="yourNumber"></span>
<span class="yourNumber1">1</span>
<span class="yourNumber1">2</span>
<span class="yourNumber1">3</span>
<span class="yourNumber1">4</span>
要更改四个元素的值,我们需要使用循环。
由于它们都包含在同一类中,因此我们使用
querySelectorAll
来获取节点。
var min = 50;
var max = 150;
var play1;
var play2;
window.onload = function () {
play1 = Math.floor(Math.random() * (max - min + 1)) + min;
max = 10 - play1; // Move max up to make play1 less than 10
document.getElementById("yourNumber").innerHTML = play1;
const spans = document.querySelectorAll(".yourNumber1"); //get nodes
spans.forEach((el) => { //loop
if (play1 < 10) { //play1 is always greater than 10
play2 = Math.floor(Math.random() * (max - min + 1)) + min;
} else {
play2 = Math.floor(Math.random() * 10) + 1;
}
el.textContent = play2;
});
};