在ZipArchive C＃.Net 4.5中创建目录

Question

ZipArchive是ZipArchiveEntries的集合，添加/删除“条目”非常有效。但似乎没有目录/嵌套“档案”的概念。理论上，该类与文件系统分离，因为您可以在内存流中完全创建存档。但是，如果要在归档中添加目录结构，则必须在条目名称前添加路径前缀。

问题：如何扩展ZipArchive以创建更好的界面来创建和管理目录？

例如，将文件添加到目录的当前方法是使用目录路径创建条目：

var entry = _archive.CreateEntry("directory/entryname");

而沿着这些方面的东西对我来说似乎更好：

var directory = _archive.CreateDirectoryEntry("directory");
var entry = _directory.CreateEntry("entryname");

Answer 1

您可以使用以下内容，换句话说，手动创建目录结构：

using (var fs = new FileStream("1.zip", FileMode.Create))
using (var zip = new ZipArchive(fs, ZipArchiveMode.Create))
{
    zip.CreateEntry("12/3/"); // just end with "/"
}

Answer 2

如果您正在处理可以使用完整.NET的项目，您可以尝试使用ZipFile.CreateFromDirectory方法，如explained here：

using System;
using System.IO;
using System.IO.Compression;

namespace ConsoleApplication
{
    class Program
    {
        static void Main(string[] args)
        {
            string startPath = @"c:\example\start";
            string zipPath = @"c:\example\result.zip";
            string extractPath = @"c:\example\extract";

            ZipFile.CreateFromDirectory(startPath, zipPath, CompressionLevel.Fastest, true);

            ZipFile.ExtractToDirectory(zipPath, extractPath);
        }
    }
}

当然，只有在基于给定目录创建新的Zips时，这才有效。

根据评论，以前的解决方案不保留目录结构。如果需要，那么以下代码可能会解决这个问题：

    var InputDirectory = @"c:\example\start";
    var OutputFilename = @"c:\example\result.zip";
    using (Stream zipStream = new FileStream(Path.GetFullPath(OutputFilename), FileMode.Create, FileAccess.Write))
    using (ZipArchive archive = new ZipArchive(zipStream, ZipArchiveMode.Create))
    {
        foreach(var filePath in System.IO.Directory.GetFiles(InputDirectory,"*.*",System.IO.SearchOption.AllDirectories))
        {
            var relativePath = filePath.Replace(InputDirectory,string.Empty);
            using (Stream fileStream = new FileStream(filePath, FileMode.Open, FileAccess.Read))
            using (Stream fileStreamInZip = archive.CreateEntry(relativePath).Open())
                fileStream.CopyTo(fileStreamInZip);
        }
    }

Answer 3

这是一个可能的解决方案：

public static class ZipArchiveExtension
{
    public static ZipArchiveDirectory CreateDirectory(this ZipArchive @this, string directoryPath)
    {
        return new ZipArchiveDirectory(@this, directoryPath);
    }
}

public class ZipArchiveDirectory
{
    private readonly string _directory;
    private ZipArchive _archive;

    internal ZipArchiveDirectory(ZipArchive archive, string directory)
    {
        _archive = archive;
        _directory = directory;
    }

    public ZipArchive Archive { get{return _archive;}}

    public ZipArchiveEntry CreateEntry(string entry)
    {
        return _archive.CreateEntry(_directory + "/" + entry);
    }

    public ZipArchiveEntry CreateEntry(string entry, CompressionLevel compressionLevel)
    {
        return _archive.CreateEntry(_directory + "/" + entry, compressionLevel);
    }
}

和使用：

var directory = _archive.CreateDirectory(context);
var entry = directory.CreateEntry(context);
var stream = entry.Open();

但我可以预见到嵌套问题。

Answer 4

我知道我迟到了（7.25.2018），

但即使使用递归目录，这对我来说也是完美无缺的。

ZipArchive的扩展文件：

public static class ZipArchiveExtension {

    public static void CreateEntryFromAny(this ZipArchive archive, String sourceName, String entryName = "") {
        var fileName = Path.GetFileName(sourceName);
        if (File.GetAttributes(sourceName).HasFlag(FileAttributes.Directory)) {
            archive.CreateEntryFromDirectory(sourceName, Path.Combine(entryName, fileName));
        } else {
            archive.CreateEntryFromFile(sourceName, Path.Combine(entryName, fileName), CompressionLevel.Fastest);
        }
    }

    public static void CreateEntryFromDirectory(this ZipArchive archive, String sourceDirName, String entryName = "") {
        string[] files = Directory.GetFiles(sourceDirName).Concat(Directory.GetDirectories(sourceDirName)).ToArray();
        archive.CreateEntry(Path.Combine(entryName, Path.GetFileName(sourceDirName)));
        foreach (var file in files) {
            var fileName = Path.GetFileName(file);
            archive.CreateEntryFromAny(file, entryName);
        }
    }

}

然后你可以打包任何东西，无论是文件还是目录：

using (var memoryStream = new MemoryStream()) {
    using (var archive = new ZipArchive(memoryStream, ZipArchiveMode.Create, true)) {
        archive.CreateEntryFromAny(sourcePath);
    }
}

Answer 5

使用子文件夹Zip文件夹的递归方法。

using System;
using System.Collections.Generic;
using System.IO;
using System.IO.Compression;

public static async Task<bool> ZipFileHelper(IFolder folderForZipping, IFolder folderForZipFile, string zipFileName)
{
    if (folderForZipping == null || folderForZipFile == null
        || string.IsNullOrEmpty(zipFileName))
    {
        throw new ArgumentException("Invalid argument...");
    }

    IFile zipFile = await folderForZipFile.CreateFileAsync(zipFileName, CreationCollisionOption.ReplaceExisting);

    // Create zip archive to access compressed files in memory stream
    using (MemoryStream zipStream = new MemoryStream())
    {
        using (ZipArchive zip = new ZipArchive(zipStream, ZipArchiveMode.Create, true))
        {
            await ZipSubFolders(folderForZipping, zip, "");
        }

        zipStream.Position = 0;
        using (Stream s = await zipFile.OpenAsync(FileAccess.ReadAndWrite))
        {
            zipStream.CopyTo(s);
        }
    }
    return true;
}

//Create zip file entry for folder and subfolders("sub/1.txt")
private static async Task ZipSubFolders(IFolder folder, ZipArchive zip, string dir)
{
    if (folder == null || zip == null)
        return;

    var files = await folder.GetFilesAsync();
    var en = files.GetEnumerator();
    while (en.MoveNext())
    {
        var file = en.Current;
        var entry = zip.CreateEntryFromFile(file.Path, dir + file.Name);                
    }

    var folders = await folder.GetFoldersAsync();
    var fEn = folders.GetEnumerator();
    while (fEn.MoveNext())
    {
        await ZipSubFolders(fEn.Current, zip, dir + fEn.Current.Name + "/");
    }
}