难以在Scala中为案例类创建伴随对象

Question

我正在使用a Kaggle dataset和Scala进行一些探索性分析。我要做的一件事情是为名为“ Taxpayer”的案例类创建一个伴随对象，如下所示：

case class Taxpayer(
                age: Int,
                workclass: String,
                education: String,
                educationNum: Int,
                maritalStatus: String,
                occupation: String,
                relationship: String,
                race: String,
                sex: String,
                capitalGain: Int,
                capitalLoss: Int,
                hoursPerWeek: Int,
                nativeCountry: String,
                income: String
              )

鉴于此案例类，我必须创建一个伴随对象并定义以下功能：

• printData：打印以下格式“ $ workclass-$ occupation-$ nativeCountry-$ income”
• apply：不带任何参数，并返回Int字段= -1和String字段=“ unknown”的Taxpayer类的实例]

我已经尝试了以下操作，但是不起作用（“预期的类或对象定义”：]

object Taxpayer{


def printData(c: Taxpayer) = {
    println(s"${c.workclass} - ${c.occupation} - ${c.nativeCountry} - ${c.income}")
    def apply(age: Int = -1, workclass: String = "unknown", education: "unknown", educationNum: Int = -1, maritalStatus: "unknown",
               occupation: "unknown", relationship: "unknown", race: "unknown", sex: "unknown", capitalGain: Int = -1,
               capitalLoss: Int = -1, hoursPerWeek: Int = -1, nativeCountry: "unknown", income: "unknown") = {
      new Taxpayer(age, workclass, education, educationNum, maritalStatus, occupation, relationship,
        race, sex, capitalGain, capitalLoss, hoursPerWeek, nativeCountry, income)
    }
  }
}
如何定义适用于数据集行的函数？先感谢您！ ：）

我正在使用带有Scala的Kaggle数据集进行一些探索性分析。我要做的一件事情是为名为“ Taxpayer”的案例类创建一个伴随对象，如下所示：case class Taxpayer（...

Answer 1

尝试