Spotify API get_playlists 未显示每周发现

Question

我有一些 Python 代码来制作一个 Flask 应用程序，它可以自动将我所有每周发现的歌曲保存到播放列表中，但它无法找到每周发现的歌曲。我让它列出了我的所有其他播放列表，它们显示得很好，我已手动关注 Spotify 中的发现每周播放列表，但它不会显示。

编辑：有人建议检查最大限制，但对我来说至少这并不适用，因为默认限制是 50，我有 41 个播放列表（包括每周发现）

def save_discover_weekly(token_info):
    sp = spotipy.Spotify(auth=token_info['access_token'])
    cur_playlists = sp.current_user_playlists()['items']
    discover_weekly_id = None
    saved_weekly_id = None
    for playlist in cur_playlists:
        print(playlist['name'])
        if playlist['name'] == 'Discover Weekly':
            discover_weekly_id = playlist['id']
            print(discover_weekly_id)
            break
        if playlist['name'] == 'Saved Weekly':
            saved_weekly_id = playlist['id']
            print(saved_weekly_id)

    if discover_weekly_id is None:
        return "Discover Weekly not found"
    if not saved_weekly_id:
        print("Creating saved weekly playlist")
        saved_weekly = sp.user_playlist_create(sp.current_user()['id'],
                                               "Saved Weekly", True)
        saved_weekly_id = saved_weekly['id']

    discover_weekly_songs = sp.playlist_items(discover_weekly_id)
    song_uris = [song['track']['uri'] for song in discover_weekly_songs['items']]

    sp.user_playlist_add_tracks(sp.current_user()['id'], saved_weekly_id, 
                                song_uris)

    return "Discover Weekly songs saved to Saved Weekly playlist!"

Answer 1

分页

许多

Spotify

端点使用 pagination 并采用一对参数：

offset

和

limit

。如果跳过，则采用默认值，这些值通常记录在相应的端点参考中。例如，当前用户的播放列表请求的默认限制为 20。

spotipy

遵循这种方式，有时使用不同的默认值。例如，

current_user_playlist

的默认限制为 50：

def current_user_playlists(self, limit=50, offset=0):
   """ Get current user playlists without required getting his profile
       Parameters:
           - limit  - the number of items to return
           - offset - the index of the first item to return
   """
   return self._get("me/playlists", limit=limit, offset=offset)

因此，对于拥有大量播放列表的用户来说，有可能无法检索足够的数据来获取所需的播放列表。您需要逐页请求这些播放列表：

MAX_LIMIT = 50
MAX_OFFSET = 100000
DISCOVER_WEEKLY = "Discover Weekly"
SPOTIFY_USER_ID = 'spotify'

def get_discover_weekly_playlist(spotify: spotipy.Spotify) -> Optional[dict]:

    for offset in range(0, MAX_OFFSET + 1, MAX_LIMIT):

        try:
            response = spotify.current_user_playlists(limit=MAX_LIMIT,
                                                      offset=offset)
        except spotipy.SpotifyException:
            break

        try:
            playlists = response['items']
        except (TypeError, KeyError):
            break

        if not playlists:
            break

        for playlist in playlists:
            if (playlist['owner']['id'] == SPOTIFY_USER_ID
                    and playlist['name'] == DISCOVER_WEEKLY):
                
                # playlist found doesn't have tracks
                # have to request the full data by id
                return spotify.playlist(playlist['id'])

    return None

搜索

考虑到边界情况，可能存在浏览播放列表比简单搜索更差的情况。通过查询“Discover Weekly”，搜索结果中似乎没有那么多公开播放列表。 Spotify 的排名也很高。它实际上可能是结果集合中的第一个播放列表。上面关于分页的所有内容仍然适用于这里：

MAX_LIMIT = 50
MAX_OFFSET = 1000
DISCOVER_WEEKLY_QUERY = "Discover Weekly"
PLAYLIST_TYPE = 'playlist'
SPOTIFY_USER_ID = 'spotify'

def get_discover_weekly(spotify: spotipy.Spotify) -> Optional[dict]:

    for offset in range(0, MAX_OFFSET + 1, MAX_LIMIT):
        try:
            response = spotify.search(q=DISCOVER_WEEKLY_QUERY, type=PLAYLIST_TYPE,
                                      offset=offset, limit=MAX_LIMIT)
        except spotipy.SpotifyException:
            break

        try:
            playlists = response['playlists']['items']
        except (TypeError, KeyError):
            break

        if not playlists:
            break

        for playlist in playlists:
            if (playlist['owner']['id'] == SPOTIFY_USER_ID
                    and playlist['name'] == DISCOVER_WEEKLY_QUERY):

                # same here, item found doesn't have tracks
                # have to request the full data by id
                return spotify.playlist(playlist['id'])

    return None