我有一个组件(卡),该组件具有使用Postgres在localhost数据库中跟踪的复选框。当我选中或取消选中该框时,条目将被放入networkusers表中。问题是,当我选中或取消选中该框,然后单击一个按钮以呈现其他组件,然后使用复选框返回到Card组件时,这些框未显示更新后的复选框。但是,如果我注销并重新登录,则所有框都将更新并与数据库同步。因此,如何更改以下组件中的复选框,如何使该组件呈现(或再次获取?)? TY。
import React, { useState } from "react";
const onUpdateCB = (ischecked, loginuser, userid, setisChecked,handleCheck,event) => {
console.log(ischecked, loginuser, userid);
fetch('http://localhost:3000/cb', {
method: 'post',
headers: {'Content-Type':'application/json'},
body:JSON.stringify({
loginuser,
userid,
ischecked: ischecked
})
}).then(setisChecked(ischecked));
};
const Card = props => {
const [isChecked, setisChecked] = useState(props.ischecked);
return (
<div
className="pointer bg-light-green dib br3 pa3 ma2 shadow-5"
onClick={() => props.handleClick(props.id)}
//onClick={(e) => e.stopPropagation()}
>
<div>
<h3>{props.name}</h3>
<p>{props.company}</p>
<p>{props.phone}</p>
<p>{props.email}</p>
<p>{props.city}</p>
</div>
<div>
My Network
<input
className="largeCheckbox"
type="checkbox"
checked={isChecked}
onClick={(event) =>
onUpdateCB(!isChecked, props.loginuser.id, props.id, setisChecked,event.stopPropagation())
}
/>
</div>
</div>
);
};
export default Card;
网络阵列
import React from "react";
import Card from "./Card";
const NetworkArray = ({
network,
networkusers,
handleChange,
handleClick,
loginuser
}) => {
console.log("in network array", networkusers);
const cardComponent = network.map((user, i) => {
const ischecked = networkusers.filter(n => {
var nw = n.id === loginuser.id && n.connections === network[i].id;
return nw;
});
console.log("i'm checked", ischecked);
return (
<Card
key={network[i].id}
name={network[i].firstname + " " + network[i].lastname}
company={network[i].company}
phone={network[i].phone}
email={network[i].email}
city={network[i].city}
ischecked={ischecked.length}
handleChange={handleChange}
handleClick={handleClick}
id={network[i].id}
loginuser={loginuser}
/>
);
});
return <div>{cardComponent}</div>;
};
export default NetworkArray;
我相信,问题出在Card
的父母中。它传递检查状态的初始值(props.ischecked
),因此您可能需要将状态更改通知它。
[您也要在onUpdateCB()
方法中输入错误-您应该使用函数作为Promise回调:
}).then(
() => setisChecked(ischecked)
);
当前您只是同时设置了选中状态。