我正在编写一个程序,该程序接收用户文件(在这种情况下为数字列表),并计算列表的均值,中位数和众数。但是,我在弄清楚如何将数字字符串转换为整数方面遇到很多麻烦。当我尝试时,出现错误:“ int()在基数10中无效的文字”,然后是列表的第一个数字。无论我尝试什么,即使这是我一直看到的解决方案,我似乎也无法转换列表。因此,当我对列表进行排序时,它不会按数字顺序进行排序。我的模式功能似乎也无法很好地工作,即使过了几天,我也不知道为什么。我会附加文件,但是似乎没有办法做到这一点,对不起。希望这是足够的信息,以查看可能导致问题的原因。
def CalculateMode(numbers):
dictionary = dict()
for num in numbers:
if num in dictionary:
dictionary[num] = dictionary[num] + 1
else:
dictionary[num] = 1
maximum = max(dictionary.values())
for key in dictionary:
if dictionary[key] == maximum:
print("The mode is " + key + ".")
def Main():
openFile = open("testfile.txt", 'r')
data = openFile.read()
numbers = data.split()
for num in numbers:
num = int(num)
return num
numbers = sorted(numbers)
print(numbers)
while True:
choice = input("Calculate Mode [1] Exit [2]: ")
if choice == "1":
CalculateMode(numbers)
elif choice == "2":
break
else:
print("Please choose one of the above options.")
Main()
以下是一个使用尽可能多的代码的选项。
注意:将变量重命名为遵循Python约定Pep 8,即:
函数名称应为小写,单词之间用强调必要以提高可读性。
变量名与函数名遵循相同的约定。
代码
import re
def calculate_mode(numbers):
dictionary = dict()
for num in numbers:
if num in dictionary:
dictionary[num] = dictionary[num] + 1
else:
dictionary[num] = 1
maximum = max(dictionary.values())
for key in dictionary:
if dictionary[key] == maximum:
print(f"The mode is {key}.")
def main():
with open("testfile.txt", 'r') as open_file:
# Extract consecutive digits using regex
# (see https://www.geeksforgeeks.org/python-extract-numbers-from-string/)
data = re.findall(r"\d+", open_file.read())
# Convert digits to integer
numbers = [int(x) for x in data]
# Sort numbers (inplace)
numbers.sort()
print(numbers)
while True:
choice = input("Calculate Mode [1] Exit [2]: ")
if choice == "1":
calculate_mode(numbers)
elif choice == "2":
break
else:
print("Please choose one of the above options.")
main()
输入文件(testfile.txt)
2, 3, 4, 5,
7, 9, 3, 2
1, 2, 9, 5
4, 2, 1, 8
6, 3, 4, 5
输出
[1, 1, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 6, 7, 8, 9, 9]
Calculate Mode [1] Exit [2]: 1
The mode is 2.
Calculate Mode [1] Exit [2]:
尝试使用int(float(desired_string))
进行投射
您尝试转换的字符串不能转换为int。
编辑:正如gold_cy所说,您的代码中存在逻辑上的不一致,这超出了所显示的错误。