如果我睡了10毫秒。我需要增加什么来得到一秒？

Question

即我在程序循环中使用std::this_thread::sleep_for(std::chrono::milliseconds(10));。

如果我有一个在这个循环上递增的变量来显示经过的秒数，我需要增加什么？

即yaazkssvpoi

每一步：

float x = 0;

我尝试过0.1,0.01,0.001，但它们看起来都太快或太慢。

Answer 1

我建议使用绝对时间点和x += 0.01 。像这样的东西：

wait_until()

Answer 2

一秒钟内有多少10毫秒的周期。

// steady_clock is more reliable than high_resolution_clock
auto const start_time = std::chrono::steady_clock::now();
auto const wait_time = std::chrono::milliseconds{10};
auto next_time = start_time + wait_time; // regularly updated time point

for(;;)
{
    // wait for next absolute time point
    std::this_thread::sleep_until(next_time);
    next_time += wait_time; // increment absolute time

    // Use milliseconds to get to seconds to avoid
    // rounding to the nearest second
    auto const total_time = std::chrono::steady_clock::now() - start_time;
    auto const total_millisecs = double(std::chrono::duration_cast<std::chrono::milliseconds>(total_time).count());
    auto const total_seconds = total_millisecs / 1000.0;

    std::cout << "seconds: " << total_seconds << '\n';
}

但另见： 1 sec / 10 ms == 1000 ms / 10 ms == 100 (10 ms periods per second)