在Laravel中验证规则的问题

Question

我在验证Laravel规则时遇到了问题。我有这个CRUD作为参数接收请求类型。我还构建了一个StoreMultipleForm，因为我有两个需要同时有效的表单。这适用于SAVE，但是，INSERT它会给出与我的CRUD请求冲突的错误：

Argument 1 passed to App\Http\Controllers\Admin\MedicosController::inserir() must be an instance of App\Http\Requests\StoreMultipleForm, instance of Illuminate\Http\Request given, called in /var/www/html/mateus/laravel/laravel-angular/app/Http/Controllers/CrudController.php on line 23

这是我的代码

CrudController.php

public function action(Request $request, $action = null, $id = null)
{
        if($action === null){
                return $this->index($id);
        }

    if (!in_array($action, $this->allowedMethods)) {
        return abort(404);
    }
    return $this->$action($request, $id);
}


UserController.php

//TYPE STOREFORMREQUEST ERROR! 
public function insert(StoreFormRequest $request){
        $user = new User;
        $user->med_crm = $request->med_crm;
        $user->med_juridico = $request->med_juridico;
        $user->med_name = $request->med_name;
        $user->save();
}

public function save(StoreFormRequest $request){
        $user = new User;
        $user->med_crm = $request->med_crm;
        $user->med_juridico = $request->med_juridico;
        $user->med_name = $request->med_name;
        $user->save();
}

代码当然不是，但重要的是参数以及SAVE的工作原理和INSERT的工作原理。

这是我的StoreMultipleForm

class StoreMultipleForm extends FormRequest
{

public function authorize()
{
    return true;
}

/**
 * Get the validation rules that apply to the request.
 *
 * @return array
 */
public function rules()
{
    $formRequests = [
      MedicoFormRequest::class,
      ConsultorioFormRequest::class,
      //PacienteFormRequest::class
    ];

    $rules = [];

    foreach ($formRequests as $source) {
      $rules = array_merge(
        $rules,
        (new $source)->rules()
      );
    }

    return $rules;
}

public function messages()
{
    $formRequests = [
      MedicoFormRequest::class,
      ConsultorioFormRequest::class,
      //PacienteFormRequest::class
    ];

    $messages = [];

    foreach ($formRequests as $source) {
      $messages = array_merge(
        $messages,
        (new $source)->messages()
      );
    }

    return $messages;
}    

}

我的路线

$this->group(['middleware' => ['auth'], 'namespace' => 'Admin'], 
   function(){
    $this->get('/admin', 'AdminController@index')->name('admin.home');
    $this->post('/admin/medicos/salvar/{id?}', 'MedicosController@salvar')->name('medicos');    
    $this->any('/admin/medicos/{action?}/{id?}', 'MedicosController@action')->name('medicos');
    $this->get('/admin/util/cidades/{uf_id}', 'UtilController@getCidadesByUf')->name('cidades');
    $this->get('/admin/especialidades/areasatuacoes/{esp_id}', 'EspecialidadeController@getAreasDeAtuacaoByEspecialidade')->name('areasatuacoes');
    $this->any('/admin/pacientes/{action?}/{id?}', 'PacientesController@action')->name('pacientes');
    $this->any('/admin/anuidades/{action?}/{id?}', 'AnuidadesController@action')->name('anuidades');    
  });

保存和插入在真正的代码中是不一样的，这里只是示例。 MedicoFormRequest是其他Request，StoreFormRequest是MedicoFormRequest和ConsultorioFormRequest之间的联结。我的问题是SAVE方法的工作原理，但INSERT不起作用。

Answer 1

基本的Http Request类被注入到你的CrudController :: action方法中，action方法试图将它传递给UserController :: insert方法，但是，该方法需要一个StoreFormRequest类，这是一个更具体的实现。请求类。

此方法不起作用，因为您无法将基类实例转换为子类实例。