我有以下3个表,并且最后从理由表中针对索赔表中的每个claimno输入了原始代码。
原因:
Rid |chargeid| enterydate user reasoncode
-----|--------|-------------|--------|----------
1 | 210 | 04/03/2018 | john | 99
2 | 212 | 05/03/2018 | juliet | 24
5 | 212 | 26/12/2018 | umar | 55
3 | 212 | 07/03/2018 | borat | 30
4 | 211 | 03/03/2018 | Juliet | 20
6 | 213 | 03/03/2018 | borat | 50
7 | 213 | 24/12/2018 | umer | 60
8 | 214 | 01/01/2019 | john | 70
收费标准:
chargeid |claim# | amount
---------|-------|---------
210 | 1 | 10
211 | 1 | 24.2
212 | 2 | 5.45
213 | 2 | 76.30
214 | 1 | 2.10
声明:
claimno | Code | Code
--------|-------|------
1 | AH22 | AH22
2 | BB32 | BB32
预期结果如下:
claimno | enterydate | user | reasoncode
--------|-------------|--------|-----------
1 | 01/01/2019 | john | 70
2 | 26/12/2018 | umer | 55
我已经应用了很多解决方案但没有运气。以下是我尝试使用SQL Server 2008时的最新解决方案,但结果仍然不正确。
With x As
(
select r.chargeid,r.enterydate,ch.claimno from charges ch
join (select chargeid,max(enterydate) enterydate,user from Reasons group by chargeid) r on r.chargeid = ch.chargeid
)
select x.*,r1.user, r1.reasoncode from x
left outer join Reasons r1 on r1.chargeid = x.chargeid and r1.enterydate = x.enterydate
--group by x.claimno
这是你想要的吗?
select claimno, enterydate, user, reasoncode
from (select c.claimno, r.*,
row_number() over (partition by c.claimno order by r.entrydate desc) as seqnum
from charges c join
reasons r
on c.chargeid = r.chargeid
) cr
where seqnum = 1;
你可以尝试使用row_number()
select * from
(
select r.chargeid,r.enterydate,ch.claimno,user,reasoncode,
row_number() over(partition by ch.claimno order by r1.enterydate desc) as rn
from charges ch left outer join Reasons r1 on r1.chargeid = ch.chargeid
)A where rn=1