试图建立有效的FEN string。
给出这个8 * 8数组示例,表示一个棋盘格,(“ 1”为空正方形):
$checkerboard = [["r","n","b","q","k","b","n","r"],["p","p","p","p","p","p","p","p"],["1","1","1","1","1","1","1","1"],["1","1","1","1","1","1","1","1"],["1","1","1","1","P","1","1","1"],["1","1","1","1","1","1","1","1"],["P","P","P","P","1","P","P","P"],["R","N","B","Q","K","B","N","R"]]
原位,这是位置:
我正在寻找的有效结果是:
rnbqkbnr/pppppppp/8/8/4P3/8/PPPP1PPP/RNBQKBNR
现在我的输出是:
rnbqkbnr/pppppppp/11111111/11111111/1111P111/11111111/PPPP1PPP/RNBQKBNR
很显然,只有当下一个条目是整数时,数组中的任何整数条目才应加到下一个整数;如果是,则应丢弃下一个条目直到结尾。
通过迭代数组,我不确定如何在此处简单地应用array_walk()或array_map()之类的内容。也许一个简单的字符串操作就足够了?
$FEN = "";
for ($i = 0;$i < 8;$i++){
for ($j = 0;$j < 8;$j++){
if ($checkerboard[$i][$j] === "1"){
if ($checkerboard[$i][$j + 1] === "1"){
/* How to iterate till the end */
$FEN .= (int)$checkerboard[$i][$j] + (int)$checkerboard[$i][$j+1];
}
} else {
$FEN .= $checkerboard[$i][$j];
}
}
$FEN .= "/";
}
任何见解?
在线示例: https://3v4l.org/tuqqo
$checkerboard = [["r","n","b","q","k","b","n","r"],["p","p","p","p","p","p","p","p"],["1","1","1","1","1","1","1","1"],["1","1","1","1","1","1","1","1"],["1","1","1","1","P","1","1","1"],["1","1","1","1","1","1","1","1"],["P","P","P","P","1","P","P","P"],["R","N","B","Q","K","B","N","R"]];
$parts = array();
foreach ($checkerboard as $innerArray) {
$num = null;
$str = '';
foreach($innerArray as $innerval){
if(is_numeric($innerval)){
$num += (int) $innerval;
}
else{
if(!is_null($num)){
$str .=$num;
$num = null;
}
$str .=$innerval;
}
}
if(!is_null($num)){
$str .=$num;
}
array_push($parts,$str);
}
$result = implode('/',$parts);
以上代码将生成所需的输出并将其存储在$ result中。