因此,我尝试编写代码以找出数字是否可以被3整除。步骤如下,输入数字,将所有数字相加,如果数字大于10,则将数字加在一起直到10以下,然后看是否剩余的数字是3、6或9,然后将其除以3,然后将其打印出来。到目前为止,这是我的代码:
user_input = int(input('Enter number: '))
sum = 0
for num in user_input:
sum += int(num)
if sum > 10:
while sum > 10:
sum = 0
for num in user_input:
sum += int(num)
if sum == 3 or 6 or 9:
print('Your number is divisble by 3')
else:
print('Your number is not divisible by 3')
else:
if sum == 3 or 6 or 9:
print('Your number is divisble by 3')
else:
print('Your number is not divisible by 3')
任何人都知道如何解决该错误吗?
替换每个:
if sum == 3 or 6 or 9:
带
if (sum in ( 3, 6, 9)):
也-不要覆盖sum
-它是python中的默认功能,您可以将变量命名为_sum
,例如。
编辑:
IIUC,这就是您想要做的(您最初插入多个以空格分隔的数字):
user_input = input('Enter numbers: ').split(" ")
for num1 in user_input:
sum = int(num1)
if sum > 10:
while sum > 10:
sum_=sum
sum=0
for num in str(sum_):
sum += int(num)
if sum in (3, 6, 9):
print(num1, ': Your number is divisble by 3')
else:
print(num1, ': Your number is not divisible by 3')
仅获取并处理单个号码:
user_input = input('Enter number: ')
sum = num1 = int(user_input)
if sum > 10:
while sum > 10:
sum_=sum
sum=0
for num in str(sum_):
sum += int(num)
if sum in (3, 6, 9):
print(num1, ': Your number is divisble by 3')
else:
print(num1, ': Your number is not divisible by 3')