如何在Python3中将文本文件转换为列表

Question

[在Python3中，从包含歌词/字幕/其他的现有.txt文件中，我想做一个简单的清单（没有任何嵌套）现有单词的集合，没有空格或其他插入符号。

基于其他StackExchange请求，我发出了这个

import csv

crimefile = open('she_loves_you.txt', 'r')
reader = csv.reader(crimefile)
allRows = list(reader) # result is a list with nested lists

ultimate = []
for i in allRows:
    ultimate += i # result is a list with elements longer than one word

ultimate2 = []
for i in ultimate:
    ultimate2 += i # result is a list with elements which are single letters

我希望的结果是

['She', 'loves', 'you', 'yeah', 'yeah', 'yeah', 'She', 'loves', 'you', ...]

================================================= ======================

同样有趣的是要理解为什么代码（它作为上述代码的扩展运行）：

import re
print (re.findall(r"[\w']+", ultimate))

带来以下错误：

Traceback (most recent call last):
  File "4.4.4.csv.into.list.py", line 72, in <module>
    print (re.findall(r"[\w']+", ultimate))
  File "/usr/lib/python3.7/re.py", line 223, in findall
    return _compile(pattern, flags).findall(string)
TypeError: expected string or bytes-like object

Answer 1

错误消息已完全清除"expected string or bytes-like object"。这意味着您的ultimate应该转换为字符串(str)，并且当您检查type的ultimate是list对象时。

>>> type(ultimate)
<class 'list'>

# or 

>>> type([])
<class 'list'>

根据您的情况；

print (re.findall(r"[\w']+", str(ultimate)))  # original text

# or

print (re.findall(r"[\w']+", ' '.join(ultimate)))  # joined words

Answer 2

尝试一下：

import csv

crimefile = open('she_loves_you.txt', 'r')
reader = csv.reader(crimefile)
allRows = list(reader) # result is a list with nested lists

ultimate = []
for i in allRows:
    ultimate += i.split(" ")