将 Golang http.Request 结构转换为 cURL 命令

Question

在微服务的调试过程中，我想知道我的客户端服务请求最终是什么样子，以确保是客户端服务的问题还是目标服务的问题。

为此，我需要一个工具（或 pkg）将

http.Request

结构转换为 cURL 命令

http.Request 结构示例：

{
    Method:POST
    URL:https://some-fake-url.com
    Proto:HTTP/1.1
    ProtoMajor:1
    ProtoMinor:1
    Accept-Encoding:[gzip, deflate, br]
    Accept-Language:[en-US,en;q=0.9]
    Authorization:[Bearer gkasgjagsljkg]
    Connection:[keep-alive]
    Content-Length:[0]
    Content-Type:[application/json]
    ...
}

客户端服务使用此请求

http.DefaultClient.Do()

,

我不想手动将其转换为 cURL，因为这可能无效。

Answer 1

您可以使用 http2curl pkg 将 Golang 请求转换为 cURL 命令，如下所示：

import (
    "http"
    "moul.io/http2curl"
)

data := bytes.NewBufferString(`{"hello":"world","answer":42}`)
req, _ := http.NewRequest("PUT", "http://www.example.com/abc/def.ghi?jlk=mno&pqr=stu", data)
req.Header.Set("Content-Type", "application/json")

command, _ := http2curl.GetCurlCommand(req)
fmt.Println(command)
// Output: curl -X PUT -d "{\"hello\":\"world\",\"answer\":42}" -H "Content-Type: application/json" http://www.example.com/abc/def.ghi?jlk=mno&pqr=stu

Answer 2

您也可以使用套餐curling

package main

import (
    "fmt"
    "log"
    "net/http"

    "github.com/aoliveti/curling"
)

func main() {
    req, err := http.NewRequest(http.MethodGet, "https://www.google.com", nil)
    if err != nil {
        log.Fatal(err)
    }
    req.Header.Add("If-None-Match", "foo")

    cmd, err := curling.NewFromRequest(req)
    if err != nil {
        log.Fatal(err)
    }

    fmt.Println(cmd)
}

输出

curl -X 'GET' 'https://www.google.com' -H 'If-None-Match: foo'