在多维数组的第三级中搜索值并返回扁平化的合格数据集

Question

我正在尝试在多维数组中搜索符合条件的条目，并以扁平关联子数组的形式返回一个或多个数据集。

输入示例：

[
    [
        'name' => 'Dick Jansen',
        'matchedMovie' => [
            [
                'nameMovie' => 'Saw',
                'genre' => 'Horror',
                'patheMovie' => 'Texas Chainsaw 3D',
                'patheMovieGenre' => 'Horror',
                'score' => '100.00',
            ]
        ]
    ],
    [
        'name' => 'Jim Scott',
        'matchedMovie' => [
            [
                'nameMovie' => 'Shooter',
                'genre' => 'Action, Thriller',
                'patheMovie' => 'The Shining',
                'patheMovieGenre' => 'Horror, Suspense/Thriller',
                'score' => '52.38',
            ],                
            [
                'nameMovie' => 'Resident Evil Movie',
                'genre' => 'Action/Horror',
                'patheMovie' => 'Texas Chainsaw 3D',
                'patheMovieGenre' => 'Horror',
                'score' => '63.16',
            ]
        ]
    ]
]

我想搜索

patheMovie

值（如“闪灵”）并获取父数组的

name

加上仅具有匹配

matchedMovie

值的

patheMovie

数组。

我的代码：

$search = 'Texas Chainsaw 3D';

$sorted = false;
foreach ($sorted as $n => $c)
    if (in_array($search, $c)) {
        $cluster = $n;
        break;
    }

如果我搜索

The Shining

，结果应该是：

array (
  0 => 
  array (
    'name' => 'Jim Scott',
    'nameMovie' => 'Shooter',
    'genre' => 'Action, Thriller',
    'patheMovie' => 'The Shining',
    'patheMovieGenre' => 'Horror, Suspense/Thriller',
    'score' => '52.38',
  ),
)

如果我搜索

Texas Chainsaw 3D

，那么结果应该是：

array (
  0 => 
  array (
    'name' => 'Dick Jansen',
    'nameMovie' => 'Saw',
    'genre' => 'Horror',
    'patheMovie' => 'Texas Chainsaw 3D',
    'patheMovieGenre' => 'Horror',
    'score' => '100.00',
  ),
  1 => 
  array (
    'name' => 'Jim Scott',
    'nameMovie' => 'Resident Evil Movie',
    'genre' => 'Action/Horror',
    'patheMovie' => 'Texas Chainsaw 3D',
    'patheMovieGenre' => 'Horror',
    'score' => '63.16',
  ),
)

Answer 1

该解决方案将取决于两个共轭环。

<?php
function searchIt($arr, $searchItem){
$result = array();
$resultIndex = 0;
for ($i =0; $i < count($arr); $i++){
 for ($j = 0; $j < count($arr[$i]['matchedMovie']); $j++){
  if ($arr[$i]['matchedMovie'][$j]['patheMovie'] == $searchItem){
   $result[$resultIndex]['name'] = $arr[$i]['name'];
    foreach ($arr[$i]['matchedMovie'][$j] as $key => $value){
     $result[$resultIndex][$key] = $value;
   }
    $resultIndex++;
  }
 } 
}
return $result;
}
?>

phpfiddle 演示

Answer 2

还没有测试过这个，但这应该有效：

function findYourGuy($array, $searchTerm) {
    $searchTerm = 'The Shining'; // testing purpose only
    foreach($array as $personArray) {
        $matchedMovies = $personArray['matchedMovie'];
        $name = $personArray['name'];
        foreach($matchedMovies as $matchedMovie) {
            if($matchedMovie['patheMovie'] == $searchTerm) {
                return array('name' => $name, 'matchedMovie' => $matchedMovie)
            }
        }
    }
    return false; //no result
}

Answer 3

我会使用array_filter。类似的东西

$movieName = 'The shining';
$result = array_filter($movies, filterCallback);

function filterCallback($var)
{
  foreach($var['matchedMovie'] as $movie) {
    if($movie['PatheMovie'] == $movieName) {
      return true;
    }
  }
}

Answer 4

因为此任务不仅需要过滤输入数组数据，还需要重组（展平）符合条件的行，因此您不能简单地使用

array_filter()

或

array_map()

作为一次性解决方案。因此，只需使用经典循环，然后在数据集合格的情况下推送扁平化的数据。

我将在外循环的签名中使用“数组解构”来享受方便的变量。

代码：（演示）

$result = [];
foreach ($movies as ['name' => $name, 'matchedMovie' => $matches]) {
    foreach ($matches as $entry) {
        if ($movieName === $entry['patheMovie']) {
            $result[] = ['name' => $name] + $entry;
        }
    }
}
var_export($result)