我知道
// C++ program for function overriding
#include <bits/stdc++.h>
using namespace std;
class base
{
public:
virtual void print ()
{ cout<< "print base class" <<endl; }
void show ()
{ cout<< "show base class" <<endl; }
};
class derived:public base
{
public:
void print () //print () is already virtual function in derived class, we could also declared as virtual void print () explicitly
{ cout<< "print derived class" <<endl; }
void show ()
{ cout<< "show derived class" <<endl; }
};
//main function
int main()
{
base *bptr;
derived d;
bptr = &d;
//virtual function, binded at runtime (Runtime polymorphism)
bptr->print();
// Non-virtual function, binded at compile time
bptr->show();
return 0;
}
我可以打印
print derived class
show base class
show derived class
我可以打印
print base class
仅通过更改d
而没有创建另一个对象的派生类的对象main()
?如果是,如何?
我可以仅通过更改
d
来使用派生类的对象main()
打印打印基类>是,可以。您必须在调用中显式使用基类。
bptr->base::print();
您也可以直接使用
d
。
d.base::print();