如何将关联角色的类似哈希的对象传递给期望哈希的构造函数?

问题描述 投票:6回答:1

我正在试验customized hashes。以下是尝试为类似配置的哈希实现更简单的查找:

use v6;

class X::Config::KeyNotFound is Exception {
    method message() {
        "Key not found!";
    }
}

# A hash that allows for nested lookup using a '.' to separate keys.
# (This means that keys themselves cannot contain a dot)
# For example:
#
#   %h = Config.new(%(a => %(b => 1)));
#   my $foo = %h<a.b>;  # <-- $foo = 1
#
class Config does Associative[Cool,Str] {
    has %.hash;

    multi method AT-KEY ( ::?CLASS:D: $key) {
        my @keys = $key.split('.');
        my $value = %!hash;
        for @keys -> $key {
            if $value{$key}:exists {
                $value = $value{$key};
            }
            else {
                X::Config::KeyNotFound.new.throw;
            }
        }
        $value;
    }

    multi method EXISTS-KEY (::?CLASS:D: $key) {
        my @keys = $key.split('.');
        my $value = %!hash;
        for @keys -> $key {
            if $value{$key}:exists {
                $value = $value{$key};
            }
            else {
                return False;
            }
        }
        return True;
    }

    multi method DELETE-KEY (::?CLASS:D: $key) {
        X::Assignment::RO.new.throw;
    }

    multi method ASSIGN-KEY (::?CLASS:D: $key, $new) {
        X::Assignment::RO.new.throw;
    }

    multi method BIND-KEY (::?CLASS:D: $key, $new){
        X::Assignment::RO.new.throw;
    }
}

my %hash = a => %(aa => 2, ab => 3), b => 4;
my %cfg := Config.new( hash => %hash );

# A dummy class to illustrate the problem:    
class MyTest {
    has %.config;
}

# Now this code does not work:
MyTest.new(
    config  => %cfg,
);

输出是:

Odd number of elements found where hash initializer expected:
Only saw: Config.new(hash => {:a(${:aa(2), :ab(3)}), :b(4)})
  in block <unit> at ./p.p6 line 70

(第70行是MyTest.new(线)

如果我将普通哈希传递给构造函数,例如使用%hash而不是%cfg,代码工作正常:

MyTest.new(
    config  => %hash,
);
perl6
1个回答
8
投票

该课程还需要做Iterable角色:

class Config does Associative[Cool,Str] does Iterable {
    ...
}

这要求实施iterator方法。在这种情况下,委托嵌套哈希的迭代器可能最容易:

method iterator() { %!hash.iterator }

有了这个,错误就解决了。 (默认的iterator给出一个迭代器,它是一个包含对象本身的1项序列,因此观察到错误。)

迭代器是必需的,因为构造具有散列属性的对象的语义是赋值,而不是绑定。当我们分配一个哈希时,我们从我们分配的东西中获取一个Iterator,并迭代它以获得要分配的值。我提到这一点,以防你的期望是有约束力的 - 也就是说,MyTest将引用Config的实例。为此,需要编写一个在BUILD中进行绑定的自定义MyTest,或者将其声明为has $.config,这意味着它只会引用Config实例,而不是将其中的值复制到新的哈希中。

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