Python 中输入后是否会被代码忽略语句？ [已关闭]

Question

我是 Python 新手，正在学习

time

模块。我正在摆弄模块，试图编写一个程序，根据用户的输入输出 UTC 或当地时间，但是当我运行该程序时，

newtime = input("Would you like to see Local or UTC time? ")

会执行，但不会执行 if 语句。

import time

newtime = input("Would you like to see Local or UTC time? ")
#newtime stores user input
if newtime.lower == "utc":
    #If newtime lowercase equals to utc this if line will run
    print(time.strftime("The current time and date in UTC is: %c ", time.gmtime()))
    #strftime formats the struct_time from gmtime() into something more readable
elif newtime.lower == "local":
    #If newtime lowercase equals to local this elif line will run
    print(time.strftime("The current time and date in local is: %c", time.localtime()))
    #strftime formats the struct_time from localtime() into something more readable
else:
    print("Input not recognized, please type 'Local' or 'UTC'")
    #If neither local or utc are inputed this prints

我认为问题可能是

newtime

，但事实并非如此。我最初有

newtime = input("Would you like to see Local or UTC time? ").lower

，因为我是编程新手，但也不是这样。

Answer 1

您需要在 if 语句中调用函数：

newtime = input("Would you like to see Local or UTC time? ")

if newtime.lower() == "utc":
    ...
elif newtime.lower() == "local":
    ...
else:
    ...

否则你只是在做：

if str.lower == 'utc':
    ...

这永远是

False

，因为函数永远不等于字符串