EclipseLink 2.7.5
具有构造函数表达式的JPQL查询。失败:Caused by: Exception [EclipseLink-0] (Eclipse Persistence Services - 2.7.5.v20191016-ea124dd158): org.eclipse.persistence.exceptions.JPQLException
Exception Description: Syntax error parsing [
SELECT NEW net.bbstats.dto.PlayerStatDto(
gl.playerId,
gl.seasonStartYear,
gl.lastName,
gl.firstName,
gl.incognito,
COUNT(DISTINCT gl.gameId) AS games,
SUM(CASE WHEN gl.hasPlayed = FALSE THEN 1 ELSE 0 END) AS gamesplayed,
SUM(CASE WHEN gl.starter = TRUE THEN 1 ELSE 0 END) AS gamesstarted,
SUM(gl.threePointersMade),
SUM(gl.freeThrowsMade),
SUM(gl.freeThrowsAttempted),
SUM(gl.personalFouls),
SUM(CASE WHEN gl.personalFouls >= 5 THEN 1 ELSE 0 END),
SUM(gl.points) AS points,
MAX(gl.points),
MIN(gl.points)
)
FROM GameLog gl
WHERE gl.roundId = :roundId AND gl.groupCode = :groupCode AND gl.rosterId IN :rosterIds
GROUP BY
gl.playerId,
gl.seasonStartYear,
gl.lastName,
gl.firstName,
gl.incognito
ORDER BY gamesstarted DESC, games DESC, points DESC, gl.lastName, gl.firstName
].
[140, 141] The constructor expression has two constructor items ('COUNT(DISTINCT gl.gameId)' and 'AS games') that are not separated by a comma.
[204, 205] The constructor expression has two constructor items ('SUM(CASE WHEN gl.hasPlayed = FALSE THEN 1 ELSE 0 END)' and 'AS gamesplayed') that are not separated by a comma.
[271, 272] The constructor expression has two constructor items ('SUM(CASE WHEN gl.starter = TRUE THEN 1 ELSE 0 END)' and 'AS gamesstarted') that are not separated by a comma.
[462, 463] The constructor expression has two constructor items ('SUM(gl.points)' and 'AS points') that are not separated by a comma.
[141, 149] The expression is invalid, which means it does not follow the JPQL grammar.
[205, 219] The expression is invalid, which means it does not follow the JPQL grammar.
[272, 287] The expression is invalid, which means it does not follow the JPQL grammar.
[463, 472] The expression is invalid, which means it does not follow the JPQL grammar.
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.buildException(HermesParser.java:157)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.validate(HermesParser.java:336)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.populateQueryImp(HermesParser.java:280)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.buildQuery(HermesParser.java:165)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.buildEJBQLDatabaseQuery(EJBQueryImpl.java:142)
at org.eclipse.persistence.internal.jpa.JPAQuery.processJPQLQuery(JPAQuery.java:225)
at org.eclipse.persistence.internal.jpa.JPAQuery.prepare(JPAQuery.java:186)
at org.eclipse.persistence.queries.DatabaseQuery.prepareInternal(DatabaseQuery.java:631)
at org.eclipse.persistence.internal.sessions.AbstractSession.processJPAQuery(AbstractSession.java:4502)
at org.eclipse.persistence.internal.sessions.AbstractSession.processJPAQueries(AbstractSession.java:4462)
at org.eclipse.persistence.internal.sessions.DatabaseSessionImpl.initializeDescriptors(DatabaseSessionImpl.java:645)
at org.eclipse.persistence.internal.sessions.DatabaseSessionImpl.postConnectDatasource(DatabaseSessionImpl.java:868)
at org.eclipse.persistence.internal.sessions.DatabaseSessionImpl.loginAndDetectDatasource(DatabaseSessionImpl.java:811)
at org.eclipse.persistence.internal.jpa.EntityManagerFactoryProvider.login(EntityManagerFactoryProvider.java:256)
at org.eclipse.persistence.internal.jpa.EntityManagerSetupImpl.deploy(EntityManagerSetupImpl.java:772)
... 201 more
这正在休眠中。我认为这是标准的JPA 2.2甚至是JPA 2.1,可以在AS
之后放置一个SELECT ...
子句,以便可以为ORDER BY
等子句重用标识符。
Q
的:怎么了?它是EclipseLink错误/缺失功能吗?因为Hibernate在这里有一些多余的肉,所以不应该那样做吗?如何在构造函数表达式中解决此问题(而不必重复ORDER BY
子句中的表达式)?
我有一个使用EclipseLink 2.7.5的带有构造函数表达式的JPQL查询。它失败并显示:原因:异常[EclipseLink-0](Eclipse Persistence Services-2.7.5.v20191016-ea124dd158):org ....
select_item
不是constructor_item
。下面是取自JPA 2.2规范的SELECT子句的语法: