汇编程序-cmp指令始终通过

Question

我正在制作井字游戏，并正在执行检查玩家是否获胜的功能。出于测试目的，我让程序在A玩家获胜时退出。刚开始时，我使程序仅检查第一行：

0，0，0 ==>此行0、0、00，0，0

当我选择程序检查的位置之一时（每次选择一个位置时，每次将A位置更改为X或O时，程序都会存在，例外在第一行）。该函数的代码在末尾

我不想包含整个代码，因为我不仅将其打印到屏幕上，还以图形模式绘制它（ah = 13h int 10h）我将仅向您展示主循环和仅过滤重要内容的checkIfWon函数。这是代码：董事会的定义：

.data
board           db 0,0,0
        db 0,0,0
        db 0,0,0
        db '$'

CheckIfWon函数：

checkIfWon proc
    ; check rows
    ; Equal to: if (board[0] == board[1] && board[1] == board[2])
    movsx   eax, byte ptr [board]
    movsx   ecx, byte ptr [board+1]
    cmp     eax, ecx
    jne     cont

    movsx   eax, byte ptr [board]
    movsx   ecx, byte ptr [board+2]
    cmp     eax, ecx
    jne     cont

    mov ax, 4c00h
    int 21h

    cont:
    ret  

ret
endp checkIfWon

.386
; mainloop
mainloop:
    ; check for exit button (ESC)...
    ; get mouse button and cursor position...
    ;;;;;;;;;;;;;;;;;;;;;;; Check if mouse is on one of the positions 

        box0:
        ; check if it got clicked...
        drawXplayer0:
        ; draw X
        jmp boxHitten
        drawOplayer0:
        ; draw o

        jmp boxHitten

    box1:
        ; check if it got clicked...
        drawXplayer1:
            ; draw X
            jmp boxHitten
        drawOplayer1:
            ; draw o

        jmp boxHitten

    box2:
        ; check if it got clicked...
        drawXplayer2:
            ; draw X
            jmp boxHitten
        drawOplayer2:
            ; draw o

        jmp boxHitten

    box3:
        ; check if it got clicked...
        drawXplayer3:
            ; draw X
            jmp boxHitten
        drawOplayer3:
            ; draw o

        jmp boxHitten

    box4:
        ; check if it got clicked...
        drawXplayer4:
            ; draw X
            jmp boxHitten
        drawOplayer4:
            ; draw o

        jmp boxHitten

    box5:
        ; check if it got clicked...
        drawXplayer5:
            ; draw X
            jmp boxHitten
        drawOplayer5:
            ; draw o

        jmp boxHitten

    box6:
        ; check if it got clicked...
        drawXplayer6:
            ; draw X
            jmp boxHitten
        drawOplayer6:
            ; draw o

        jmp boxHitten

    box7:
        ; check if it got clicked...
        drawXplayer7:
            ; draw X
            jmp boxHitten
        drawOplayer7:
            ; draw o

        jmp boxHitten

    box8:
        ; check if it got clicked...
        drawXplayer8:
            ; draw X
            jmp boxHitten
        drawOplayer8:
            ; draw o

        jmp boxHitten

    boxHitten:  
        ; Fix overdrawn borders
        call drawBoard

        ; set cursor position 
        mov  dl, 1
        mov  dh, 1
        mov  bh, 0    ;Display page     
        mov  ah, 02h  ;SetCursorPosition
        int  10h
        ;
        ; change player
        ; if player='x': player='O' else player=x'

        ; here im playing a sound that tells the user he clicked


        ; delay
        push 500 ; 0.5 secs
        call delay
        call checkIfWon
        jmp mainloop

    takenError:
        push 14000 ; frequency for bad answer
        push 200       ; duration milliseconds
        call play

        ; delay
        push 1000
        call delay
        jmp mainloop

程序没有退出（如我想要的那样：存在（不是我想要的）：

程序跳过它的原因可能是什么？

编辑：我想我知道原因，正在调查...

Answer 1

我想出了解决问题的方法：事情是，因为我将板定义为

board db 0,0,0分贝0,0,0分贝0,0,0

每次检查都是简单的，因为它们都是0。当我单击该位置的东西时，面板变为[]

板X，0,00,0,00,0,0

然后它没有通过检查。解决方案代码：

checkIfWon proc
     ; check rows
     ; Equal to: if (board[0] != 0 && board[0] == board[1] && board[1] == board[2])
     movsx   eax, byte ptr [board]
     movsx   ecx, byte ptr [board+1]
     cmp     eax, 0
     je cont
     cmp     eax, ecx
     jne     cont

     movsx   eax, byte ptr [board]
     movsx   ecx, byte ptr [board+2]
     cmp     eax, ecx
     jne     cont

     mov ax, 4c00h
     int 21h

cont:
    ret  

ret
endp checkIfWon