Reportlab - Unicode字符显示为unicode支持的字体框

Question

尝试通过python 3使用reportlab来编写包含macrons（āēīōū）的文档，但是macrons显示为框（■）。该文档是用Arial字体编写的 - 但是如果我在文字处理器中打开文件来检查字体，那么这些框就是“Segoe UI Symbol”字体。

用于在Arial中导入为支持广泛的unicode字符的字体（似乎有效）：

import reportlab.rl_config
reportlab.rl_config.warnOnMissingFontGlyphs = 0
from reportlab.pdfbase import pdfmetrics
from reportlab.pdfbase.ttfonts import TTFont
pdfmetrics.registerFont(TTFont('Arial', 'Arial.ttf'))

我还通过json导入一个字典，当我在记事本中打开json文件时看起来像这样：

{"example1":"b\u0101s"}

该程序读写这个字典：

from reportlab.platypus import SimpleDocTemplate, Paragraph, Spacer
from reportlab.lib.styles import getSampleStyleSheet
doc = SimpleDocTemplate("hello.pdf")
Story = [Spacer(1,2*inch)]
style = styles["Normal"]
with open('CompDict.json','r') as f:
        m_dic=json.load(f)
for key,value in m_dic:
     p=Paragraph(key+":"+value,style)
     Story.append(p)
doc.build(Story)

结果应该是与example1:bās的pdf，而是作为example1:b■s

Answer 1

在此链接下找到您的角色：

UTF-8 encoding table and Unicode characters

1. 转到表格的（utf-in literal）行。
2. 你会看到一些：\xc3\x85喜欢的字符。选择你的角色......
3. 然后对于文本输出，在您的代码中输入类似于： Canvas.drawString(x,y,'\xc3\x85') =>它将打印Å ...

所以你必须把你的字典项改为UTF-8 LITERALS，因为它不会理解"b\u0101s"Unicode，有很多方法可以做到这一点......

最好的祝福

Answer 2

#Here I am writing chunks of code, hope you will understand

from reportlab.platypus import Paragraph, SimpleDocTemplate, Spacer  
from reportlab.lib.styles import getSampleStyleSheet, ParagraphStyle   
from reportlab.lib.enums import TA_CENTER,TA_JUSTIFY       
from reportlab.pdfbase import pdfmetrics      
from reportlab.pdfbase.ttfonts import TTFont   
from reportlab.lib.fonts import addMapping

pdfmetrics.registerFont(TTFont('devaNagri', 'NotoSerifDevanagari.ttf')) # devaNagri is a folder located in **/usr/share/fonts/truetype** and 'NotoSerifDevanagari.ttf' file you just download it from https://www.google.com/get/noto/#sans-deva and move to devaNagri folder.

addMapping('devaNagri', 0, 0, 'NotoSerifDevanagari') #devnagri is a folder name and NotoSerifDevanagari is file name 

style = getSampleStyleSheet()   
style.add(ParagraphStyle(name="ParagraphTitle", alignment=TA_JUSTIFY, fontName="devaNagri")) # after mapping fontName define your folder name.   
paragraph = Paragraph('your unicode string', style["ParagraphTitle"])