查找字符串中字符的位置

Question

如何在

String

中找到字符并打印该字符在整个字符串中的位置？例如，我想在这个字符串中找到

'o'

的位置：

"you are awesome honey"

并得到答案=

1 12 17

。

我写了这个，但它不起作用：

public class Pos {
    public static void main(String args[]){
        String string = ("You are awesome honey");
        for (int i = 0 ; i<string.length() ; i++)
        if (string.charAt(i) == 'o')
        System.out.println(string.indexOf(i));
    }
}

Answer 1

你几乎是对的。问题是你的最后一行。您应该打印

i

而不是

string.indexOf(i)

:

public class Pos{
    public static void main(String args[]){
        String string = ("You are awesome honey");
        for (int i = 0 ; i<string.length() ; i++)
        if (string.charAt(i) == 'o')
        System.out.println(i);
    }
}

Answer 2

从第一个字符开始，迭代所有字符，直到到达末尾。在每个步骤中测试该字符是否是“o”。如果是，则打印位置。

Answer 3

这里是 Java：

    String s = "you are awesome honey";
    char[] array = s.toCharArray();
    for(int i = 0; i < array.length; i++){
        if(array[i] == 'o'){
            System.out.println(i);
        }   
    }

Answer 4

    static ArrayList<String> getCharPosition(String str, char mychar) {
            ArrayList<String> positions = new ArrayList<String>();

            if (str.length() == 0)
                return null;

            for (int i = 0; i < str.length(); i ++) {
                if (str.charAt(i) == mychar) {
                    positions.add(String.valueOf(i));
                }
            }

            return positions;
    }

String string = ("You are awesome honey");

ArrayList<String> result = getCharPosition(string, 'o');

for (int i = 0; i < result.size(); i ++) {
    System.out.println("char position is: " + result.get(i));
}

输出：

char position is: 1
char position is: 12
char position is: 17

Answer 5

这是查找字符串中特定字符的所有位置的函数

public ArrayList<Integer> findPositions(String string, char character) {
    ArrayList<Integer> positions = new ArrayList<>();
    for (int i = 0; i < string.length(); i++){
        if (string.charAt(i) == character) {
           positions.add(i);
        }
    }
    return positions;
}

并使用它

ArrayList<Integer> result = findPositions("You are awesome honey",'o'); 
// result will contains 1,12,17

Answer 6

public class Test {
    //Please remember that the first array position will always start from 0
    public static void main(String[] args){
        String name = ("Renuncia Boric!!!");
        for (int i = 0 ; i<name.length() ; i++)
            if (name.charAt(i) == 'i')
                System.out.println("The letter selected is present at the position: "+i+".");
    }
}

输出：

The letter selected is present at the position: 6.
The letter selected is present at the position: 12.