如何使用Java将八位字节流读取为纯字符串/文本？

Question

我有一些来自请求的内容，该请求已保存到.txt文件。

POST /domibus/services/...
Host: domibusbackend
Connection: close
Content-Length: 16189
Content-Type: multipart/related; type="application/soap+xml"; boundary="uuid:6b5b42a6-ea2f-4830-84c3-c799f38ca32a"; start="<[email protected]>"; start-info="application/soap+xml"
Accept: */*
User-Agent: Apache-CXF/3.3.2
Cache-Control: no-cache
Pragma: no-cache

.........

Content-Type: application/octet-stream
Content-Transfer-Encoding: binary
Content-ID: <[email protected]>
CompressionType: application/gzip
MimeType: application/xml

­†’^tÜ:–jq®Z{€Üş˝`cWłÓx˘ěxĐWé"v«8-ňBStÂá›Ë+•jnCćcv‰v2—ťř‘÷ż÷ ĺůéűI˝sJá@Vzľ¸…“ߟ¤Ž2]§yÁbů,m ĺgٱťŠ¸áĐĽ<í.ÖÚeGü®î…Č>
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有人可以告诉我如何将这些数据转换为人类可读的数据吗？它在标头中说应该是二进制的，但事实并非如此，二进制数据看起来有所不同。如果有人可以帮助我，我将不胜感激。谢谢！

Answer 1

此建议压缩：CompressionType: application/gzip

将主体放入java.util.zip.GZIPInputStream

Answer 2

我假设您正在使用Servlet-API

public void doPost(HttpServletRequest request, HttpServletResponse response) {
    InflaterInputStream is = InflaterInputStream(request.getInputStream()); 
    String readableString = extract(is);
    // do the processing
}

然后将压缩的二进制数据转换为可读的字符串

private String extract(InputStream is) throws IOException {
    StringBuffer sb = new StringBuffer();
    BufferedReader in = new BufferedReader(new InputStreamReader(is));
    String inputLine = "";
    while ((inputLine = in.readLine()) != null) {
        sb.append(inputLine);
    }
    return sb.toString();
}