有什么办法可以让客户端的原始IP地址进入服务器吗?我可以使用request.getRemoteAddr()
,但我似乎总是得到代理或Web服务器的IP。
我想知道客户端用来连接我的IP地址。无论如何我能得到它吗?
试试这个:
public static String getClientIpAddr(HttpServletRequest request) {
String ip = request.getHeader("X-Forwarded-For");
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("HTTP_CLIENT_IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("HTTP_X_FORWARDED_FOR");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getRemoteAddr();
}
return ip;
}
InetAddress inetAddress = InetAddress.getLocalHost();
String ip = inetAddress.getHostAddress();
request.getRemoteAddr()
就是这样。您的代理似乎更改了源IP。当某些代理执行此操作时,他们会在某些自定义http标头中添加原始IP。使用request.getHeaderNames()
和request.getHeaders(name)
并打印所有这些以查看是否没有任何感兴趣的内容。像X-CLIENT-IP
(做了一个,但他们看起来像这样)
我用过的最好的解决方案
public String getIpAddr(HttpServletRequest request) {
String ip = request.getHeader("x-forwarded-for");
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("Proxy-Client-IP");
}
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getRemoteAddr();
}
return ip;
}
你不能以有意义的方式做到这一点。
代理可能会也可能不会添加代理头,但在很多情况下,这将是一个内部唯一的地址,所以对你来说没有意义。组织边缘的大多数代理都被配置为尽可能少地揭示网络的内部结构。
您打算将这些信息用于什么?
由于这通常是部署问题,而不是应用程序问题,另一种方法是适当地配置应用程序容器。配置完成后,容器会负责检查相应的标题,您的应用程序将继续使用request.getRemoteAddr()
。
例如,在Tomcat中,您可以使用Remote IP Valve。我认为大多数应用服务器都具有类似的功能。
如果您的前端负载均衡器正在终止SSL连接,并通过HTTP将请求转发到应用服务器,则容器还可以了解情况。当您的应用程序需要为自己生成URL时,这很重要。
如果使用代理或负载均衡器,“x-forwarded-for”请求标头包含原始客户端IP。但我认为并非所有代理/ lb都添加此标头。
这里有一些解析标题的java代码:http://www.codereye.com/2010/01/get-real-ip-from-request-in-java.html
如果这个标题不存在,那么我会像@Bozho建议的那样继续
String ipAddress = request.getHeader("x-forwarded-for");
if (ipAddress == null) {
ipAddress = request.getHeader("X_FORWARDED_FOR");
if (ipAddress == null){
ipAddress = request.getRemoteAddr();
}
}
为什么不使用这样更优雅的解决方案?
private static final List<String> IP_HEADERS = Arrays.asList("X-Forwarded-For", "Proxy-Client-IP", "WL-Proxy-Client-IP", "HTTP_CLIENT_IP", "HTTP_X_FORWARDED_FOR");
public static String getClientIpAddr(HttpServletRequest request) {
for (String ipHeader : IP_HEADERS) {
String ip = request.getHeader(ipHeader);
if (ip != null && !ip.isEmpty() && !ip.equalsIgnoreCase("unknown")) {
return ip;
}
}
return request.getRemoteAddr();
}
重复编码你的代码!
为什么我认为我们应该首先尝试从标题'X-Forwarded-For
'获取IP?如果你从request.getRemoteAddr()
,它可能是client's real ip or last proxy's ip which forwards the request。因此,我们无法分辨它属于哪种情况。但是,如果将'X-Forwarded-For
'设置到标头中,则客户端IP必然是您从中获取的最左侧部分。
/**
* Try to get real ip from request:
* <ul>
* <li>try X-Forwarded-For</li>
* <li>try remote address</li>
* </ul>
*
* @param request request
* @return real ip or ""
*/
private String tryGetRealIp(HttpServletRequest request) {
// X-Forwarded-For: <client>, <proxy1>, <proxy2>
// If a request goes through multiple proxies, the IP addresses of each successive proxy is listed.
// This means, the right-most IP address is the IP address of the most recent proxy and
// the left-most IP address is the IP address of the originating client.
String forwards = request.getHeader("X-Forwarded-For");
if (StringUtils.isNotBlank(forwards)) {
// The left-most IP must be client ip
String ip = StringUtils.substringBefore(forwards, ",");
return ip;
} else if (StringUtils.isNotBlank(request.getRemoteAddr())) {
// this could be real client ip or last proxy ip which forwards the request
return request.getRemoteAddr();
}
return "";
}