如何在 db raw laravel 中添加条件?

问题描述 投票:0回答:3

我的查询 db raw laravel 像这样:

public function getTopProduct($price = null) {
    $products =  DB::select(DB::raw('SELECT * 
                    FROM (
                        SELECT a.*, b.name AS store_name, b.address
                        FROM products a
                        JOIN stores b ON b.id = a.store_id
                        WHERE a.status = 1                                                
                    ) AS product
                    GROUP BY store_id')
        );
    return $products;
}

我要添加条件

如果价格不为空,则会在

where

上添加条件价格

例如价格=1000,那么在

where
上查询如下:

WHERE a.status = 1 AND a.price < 1000

如果价格 = null,则条件

AND a.price < 1000
不执行

我该怎么做?

更新

我稍微改变了我的代码流程

我尝试这样:

public function getTopProduct($price)
{
    if($price == 1)
        $price_condition = 'WHERE price > 1000';
    else if($price == 2)
        $price_condition = 'WHERE price >= 500 AND a.price <= 1000';
    else if($price == 3)
        $price_condition = 'WHERE price < 500';
    else
        $price_condition = '';


    $products = DB::select('SELECT * 
                    FROM (
                        SELECT a.*, b.name AS store_name, b.address
                        FROM products a
                        JOIN stores b ON b.id = a.store_id
                        WHERE a.status = 1                                                
                    ) AS product
                    GROUP BY store_id
                    '.$price_condition
                );
    return $products;
}

而且有效

你觉得怎么样?

我的解决方案是否正确?或者你有更好的解决方案吗?

mysql laravel laravel-5 laravel-5.3 eloquent
3个回答
0
投票
public function getTopProduct($price = null) {
if($price==null){
         $products =  DB::select(DB::raw('SELECT * 
                FROM (
                    SELECT a.*, b.name AS store_name, b.address
                    FROM products a
                    JOIN stores b ON b.id = a.store_id
                    WHERE a.status = 1                                                
                ) AS product
                GROUP BY store_id')
    );
 }else{
       $products =  DB::select(DB::raw('SELECT * 
                FROM (
                    SELECT a.*, b.name AS store_name, b.address
                    FROM products a
                    JOIN stores b ON b.id = a.store_id
                    WHERE a.status = 1 AND a.price='.$price.'                                                
                ) AS product
                GROUP BY store_id')
    );
 }
 return $products;
}

0
投票

您可以在查询生成器中使用高级连接子句

DB::table('products') ->join('stores', function ($join) use ($price) { $query = $join->on('stores.id', '=', 'products.store_id') ->where('products.status', '=', 1); if (!empty($price)) { $query->where('products.price', '<', 1000); } }) ->select('products.*', 'stores.name AS store_name', 'stores.address') ->groupBy('products.store_id') ->get();
    

0
投票
根据您的

where

 条件尝试类似以下代码:

$price = array_column($request->get('price'), 'id');

$price = $request->get('price');



$query = DB::select(DB::raw('SELECT * FROM ( SELECT a.*, b.name AS store_name, b.address FROM products a JOIN stores b ON b.id = a.store_id WHERE a.status = 1 ) AS product GROUP BY store_id')) ->when($price == 1, function($query) use ($price) { $query->where('price', '>', '1000'); }) ->when($price == 2, function($query) use ($price) { $query->where('price', '>=', '500') ->where('a.price', '<=', '1000'); }) ->when($price == 3, function($query) use ($price) { $query->where('price', '<', '500'); }) ->when($price == '', function($query) use ($price) { $query->where('your_where_when_price_empty'); }) ->get();

希望这对您有帮助!

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