如何在'if'语句中使用多个'or'布尔运算符在python中执行不同类型的任务？ [重复]

Question

我真的不知道这个问题怎么说，但我希望“h”或“j”或“k”输入显示它们各自的值

from pynput.keyboard import Key, Controller
import time
import random

keyboard = Controller()

wasd = ["w","a","s","d","j","h","k"]

for x in range(1,11):
    if wasd[random.randint(0,6)] == "w":
        keyboard.press("w")
        time.sleep(0.5)
        keyboard.release("w")
    elif wasd[random.randint(0,6)] == "a":
        keyboard.press("a")
        time.sleep(1)
        keyboard.release("a")
    elif wasd[random.randint(0,6)] == "s":
        keyboard.press("s")
        time.sleep(0.1)
        keyboard.release("s")
    elif wasd[random.randint(0,6)] == "d":
        keyboard.press("d")
        time.sleep(1)
        keyboard.release("d")
    elif wasd[random.randint(0,6)] == "h" or "j" or "k":
        keyboard.press("h" or "j" or "k")
        time.sleep(0.03)
        keyboard.release("h" or "j" or "k") 

这是代码，这是输出：shdhswhhhh

所以只要它是 h、j 或 k，它只输入 h

Answer 1

在您提供的代码中，以下一行是不正确的：

elif wasd[random.randint(0,6)] == "h" or "j" or "k":

这行代码始终为 True，因为“j”和“k”是非空字符串，在 Python 中被认为是 True。因此，这种情况下的代码块每次都会执行，并且总是输入“h”。

要解决此问题，您可以将行更改为：

elif wasd[random.randint(0,6)] in ["h", "j", "k"]:

此代码将检查随机元素是否来自 wasd。如果是，则执行此条件下的代码块，并键入相应的字符。

另外，keyboard.press("h" or "j" or "k") will always press "h".

所以你可以把它改成

keyboard.press(random.choice(["h", "j", "k"]))