我正在尝试使用Java并发包的ExecutorService SingleThreadExecutor执行一个可运行的对象。当我在新的Runnable对象上调用execute一个命令时,它只是跨过它。即不调用run()方法。
我已经使用调试器逐步完成了我的代码行,并且可以看到我的SingleThreadExecutor已经创建并且我的Runnable已初始化。
public class RunnableDemo {
public ExecutorService executor;
public RunnableDemo () {
this.executor = Executors.newSingleThreadExecutor();
}
public void start(){
executor.execute(new MyRunnable("Hello World"));
}
public static void main(String[] args){
RunnableDemo app = new RunnableDemo();
app.start();
}
}
public class MyRunnable implements Runnable {
private String strToPrint;
public MyRunnable(String parameter) {
this.strToPrint = parameter;
}
public void run() {
System.out.println(strToPrint);
}
}
并且可能是不言自明的,但在这种情况下,我希望看到“Hello World”打印到屏幕上。但是,在创建runnable后似乎不会调用execute / run方法。
您的程序在执行程序启动任务之前终止。
你必须等待执行者完成这样的事情:
public class RunnableDemo {
public ExecutorService executor;
public RunnableDemo () {
this.executor = Executors.newSingleThreadExecutor();
}
public void start(){
executor.execute(new MyRunnable("Hello World"));
}
public void awaitTermination(){
try {
service.awaitTermination(10, TimeUnit.SECONDS);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static void main(String[] args){
RunnableDemo app = new RunnableDemo();
app.start();
app.awaitTermination();
}
}
public class MyRunnable implements Runnable {
private String strToPrint;
public MyRunnable(String parameter) {
this.strToPrint = parameter;
}
public void run() {
System.out.println(strToPrint);
}
}