用循环检查JavaScript Tic Tac Toe冠军的好方法是什么

Question

我正在寻找一种使用for循环或替代解决方案来检查Tic Tac Toe冠军的好方法。

到目前为止我尝试过的循环是这个

  $(document).ready(function() {
  var huPlayer, computer;
  var huPlayerArr = [], computerArr = [];
  var occupiedCells = [];
  var winningCombos = [
    [1,2,3],[4,5,6],[7,8,9],[1,4,7],[2,5,8],[3,6,9],[1,5,9],[3,5,7]
  ];

  $cell = $('.cell');

  $('#myModal').modal('show');

  $('.select').click(function() {
    let turnX = 'X';
    let turnO = 'O';
    $(this).attr("data-dismiss", "modal");
    huPlayer = $(this).text() 
    computer = huPlayer === turnX ? turnO: turnX; 
    $('.player').append(`<div class="alert-success">You chose to play as ${huPlayer}</div>`);
  });

  function resetGame() {
    huPlayer = undefined;
    computer = undefined;
    huPlayerArr = [];
    computerArr = [];
    occupiedCells = [];

  }

  // Min max function
  function generateRandomNumber(min, max) {
    return Math.floor(Math.random()*(max-min+1)+min);
  }

  function isEmpty(el) {
    if ($.trim($(el).html()) == '') {
      return true;
    };
  }

  function insertMarker(text, val, id) {
    occupiedCells.push(+id);
    text.html(val);
  }

  // Check winner
  function isThereAWinner(arr) {
    for (let i = 0; i < winningCombos.length; i++) {
      if (arr.indexOf(winningCombos[i][0] == 1)
      && arr.indexOf(winningCombos[i][1] == 1
      &&  arr.indexOf(winningCombos[i][0] == 1))) {
        console.log("There's a winner");
      }
    }
  }

  $cell.click(function() {
    if (huPlayer === undefined && computer === undefined) {
      $('#myModal').modal('show');
    } 
    else {
      var id = $(this).attr("id");
      if (isEmpty(id)) {
        insertMarker($(this), huPlayer, id);
        huPlayerArr.push(id);
        console.log(huPlayerArr); 

        if (isThereAWinner(huPlayerArr)) {
          console.log("There's a winner");
        }
        else if (occupiedCells.length === 9) {
          console.log("Tie game");
        }
      }
    }
  });
});

我希望人类玩家每次在单元格中单击时都调用此函数，然后AI应该随机插入一个标记。我不确定如何为AI实现min max功能。

Answer 1

对于每个winningCombos数组，如果在arr中存在该获胜组合中的三个正方形ID，则您有一个获胜者：

function isThereAWinner(arr) {
    for (let i = 0; i < winningCombos.length; i++) {
        if (
            arr.includes( winningCombos[i][0] )
                &&
            arr.includes( winningCombos[i][1] )
                &&
            arr.includes( winningCombos[i][2] )
    ) {
        console.log("There's a winner");
        break;
    }
}