C#ZipArchive - 如何在不写入磁盘的情况下嵌套内部.zip文件

问题描述 投票:3回答:2

我需要在内存中创建一个zip文件,然后将zip文件发送到客户端。但是,在某些情况下,创建的zip文件需要包含也在内存中生成的其他zip文件。例如,文件结构可能如下所示:

 SendToClient.zip
   InnerZip1.zip
     File1.xml
     File2.xml
   InnerZip2.zip
     File3.xml
     File4.xml

我一直在尝试使用System.IO.Compression.ZipArchive库。我无法使用System.IO.Compression.ZipFile库,因为我的项目的.NET版本与它不兼容。

这是我尝试过的一个例子。

public Stream GetMemoryStream() {
    var memoryStream = new MemoryStream();
    string fileContents = "Lorem ipsum dolor sit amet";
    string entryName = "Lorem.txt";
    string innerZipName = "InnerZip.zip";
    using (var archive = new ZipArchive(memoryStream, ZipArchiveMode.Create, true)) {
        ZipArchiveEntry entry = archive.CreateEntry(Path.Combine(innerZipName, entryName), CompressionLevel.Optimal);
        using (var writer = new StreamWriter(entry.Open())) {
             writer.Write(fileContents);
        }
    }
    return memoryStream
}

但是,这只是将Lorem.txt放在名为“Inner.zip”的文件夹中(而不是在实际的zip文件中)。

如果我创建一个名为“Inner.zip”的条目而不写入它,我可以创建一个空的内部zip文件。但是我无法添加任何东西,然后写入名为“Inner.zip \ Lorem.txt”的条目只是再次创建一个文件夹(旁边同名的空.zip文件)。

我还尝试创建一个单独的存档,使用内存流将其序列化,然后将其作为.zip写入原始存档。

public Stream CreateOuterZip() {
    var memoryStream = new MemoryStream();
    using (var archive = new ZipArchive(memoryStream, ZipArchiveMode.Create, true)) {
        ZipArchiveEntry entry = archive.CreateEntry("Outer.zip", CompressionLevel.NoCompression);
        using (var writer = new BinaryWriter(entry.Open())) {
            writer.Write(GetMemoryStream().ToArray());
        }
    }
    return memoryStream;
}

这只会创建一个无效的.zip文件,Windows不知道如何打开。

提前致谢!

c# stream zip
2个回答
2
投票

所以我创建了一个FileStream而不是MemoryStream,因此可以更轻松地测试代码

public static Stream CreateOuterZip()
        {
            string fileContents = "Lorem ipsum dolor sit amet";

            // Final zip file
            var fs = new FileStream(
                Path.Combine(AppDomain.CurrentDomain.BaseDirectory, "SendToClient.zip"), FileMode.OpenOrCreate);

            // Create inner zip 1
            var innerZip1 = new MemoryStream();
            using (var archive = new ZipArchive(innerZip1, ZipArchiveMode.Create, true))
            {
                var file1 = archive.CreateEntry("File1.xml");
                using (var writer = new BinaryWriter(file1.Open()))
                {
                    writer.Write(fileContents); // Change fileContents to real XML content
                }
                var file2 = archive.CreateEntry("File2.xml");
                using (var writer = new BinaryWriter(file2.Open()))
                {
                    writer.Write(fileContents); // Change fileContents to real XML content
                }
            }

            // Create inner zip 2
            var innerZip2 = new MemoryStream();
            using (var archive = new ZipArchive(innerZip2, ZipArchiveMode.Create, true))
            {
                var file3 = archive.CreateEntry("File3.xml");
                using (var writer = new BinaryWriter(file3.Open()))
                {
                    writer.Write(fileContents); // Change fileContents to real XML content
                }
                var file4 = archive.CreateEntry("File4.xml");
                using (var writer = new BinaryWriter(file4.Open()))
                {
                    writer.Write(fileContents); // Change fileContents to real XML content
                }
            }

            using (var archive = new ZipArchive(fs, ZipArchiveMode.Create, true))
            {
                // Create inner zip 1
                var innerZipEntry = archive.CreateEntry("InnerZip1.zip");
                innerZip1.Position = 0;
                using (var s = innerZipEntry.Open())
                {
                    innerZip1.WriteTo(s);
                }

                // Create inner zip 2
                var innerZipEntry2 = archive.CreateEntry("InnerZip2.zip");
                innerZip2.Position = 0;
                using (var s = innerZipEntry2.Open())
                {
                    innerZip2.WriteTo(s);
                }
            }

            fs.Close();
            return fs; // The file is written, can probably just close this
        }

您可以明显地修改此方法以返回MemoryStream,或将方法更改为Void以将zip文件写入磁盘


2
投票

您还应该为内部zip文件创建ZipArchive。将其写入流(memorystream)。并将此流作为一般流写入主zip。

    static Stream Inner() {

      var memoryStream = new MemoryStream();
      using (var archive = new ZipArchive(memoryStream, ZipArchiveMode.Create, true)) {

        var demoFile = archive.CreateEntry("foo2.txt");

        using (var entryStream = demoFile.Open())
        using (var streamWriter = new StreamWriter(entryStream)) {
          streamWriter.Write("Bar2!");
        }
      }
      return memoryStream;
    }

    static void Main(string[] args) {

      using (var memoryStream = new MemoryStream()) {
        using (var archive = new ZipArchive(memoryStream, ZipArchiveMode.Create, true)) {

          var demoFile = archive.CreateEntry("foo.txt");

          using (var entryStream = demoFile.Open())
          using (var streamWriter = new StreamWriter(entryStream)) {
            streamWriter.Write("Bar!");
          }

          var zip = archive.CreateEntry("inner.zip");
          using (var entryStream = zip.Open()) {
            var inner = Inner();
            inner.Seek(0, SeekOrigin.Begin);
            inner.CopyTo(entryStream);
          }
        }

        using (var fileStream = new FileStream(@"d:\test.zip", FileMode.Create)) {
          memoryStream.Seek(0, SeekOrigin.Begin);
          memoryStream.CopyTo(fileStream);
        }
      }

感谢this的回答。

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