这个问题在这里已有答案:
嘿,所以我是PDO的新手,我无法弄清楚为什么我的数据不会插入到我的表中。非常感激!
<?php
include("class.php");
$dbhost = "localhost";
$dbname = "db";
$dbuser = "user";
$dbpass = "pass";
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);
$username = $_POST['username'];
$password = $_POST['password'];
$email = strtolower($_POST['email']);
$firstName = ucwords(strtolower($_POST['firstName']));
$lastName = ucwords(strtolower($_POST['lastName']));
$date = date("Y-m-d");
$hash = Secure::Encrypt($username, $password);
$sql = "INSERT INTO users (username,password,email,firstName,lastName,createDate) VALUES (:username,:password,:email,:firstName,:lastName,:date)";
$q = $conn->prepare($sql);
$q->execute(array(
':username'=>$username,
':password'=>$hash,
':email'=>$email,
':firstName'=>$firstName,
':lastName'=>$lastName,
':date'=>$date));
?>
如果你的所有表的字段名都匹配,我发现如果你的一个数组变量为空,PDO有时会失败。
要查明是否有任何错误被抛出,请在new PDO
声明后添加以下内容(PDO错误报告默认为静默):
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
然后在每个PDO活动周围添加try
/ catch
,如下所示:
try {
..Code Here...
}catch (PDOException $err) {
echo $err->getMessage();
}
最终守则:
<?php
include("class.php");
$dbhost = "localhost";
$dbname = "db";
$dbuser = "user";
$dbpass = "pass";
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$username = $_POST['username'];
$password = $_POST['password'];
$email = strtolower($_POST['email']);
$firstName = ucwords(strtolower($_POST['firstName']));
$lastName = ucwords(strtolower($_POST['lastName']));
$date = date("Y-m-d");
$hash = Secure::Encrypt($username, $password);
$sql = "INSERT INTO users (username,password,email,firstName,lastName,createDate) VALUES (:username,:password,:email,:firstName,:lastName,:date)";
try {
$q = $conn->prepare($sql);
}catch (PDOException $err) {
echo 'Prepare Failed: '.$err->getMessage();
}
try {
$q->execute(array(
':username'=>$username,
':password'=>$hash,
':email'=>$email,
':firstName'=>$firstName,
':lastName'=>$lastName,
':date'=>$date));
}catch (PDOException $err) {
echo 'Execute Failed: '.$err->getMessage();
}
?>
那么请更新你收到的任何错误:)
首先,在try
-catch
块中插入可能出错的所有内容(例如数据库连接)是一种很好的做法。
try {
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch (PDO Exception $e) {
return $e;
}
你的sql语句中有一个错误。你需要在反引号(`)中放置表和列的名称
INSERT INTO `users` (`username`,`password`,`email`,`firstName`,`lastName`,`createDate`) VALUES (:username,:password,:email,:firstName,:lastName,:date)
最终代码:
<?php
include("class.php");
$dbhost = "localhost";
$dbname = "db";
$dbuser = "user";
$dbpass = "pass";
try {
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch (PDO Exception $e) {
return $e;
}
$username = $_POST['username'];
$password = $_POST['password'];
$email = strtolower($_POST['email']);
$firstName = ucwords(strtolower($_POST['firstName']));
$lastName = ucwords(strtolower($_POST['lastName']));
$date = date("Y-m-d");
$hash = Secure::Encrypt($username, $password);
$sql = "INSERT INTO `users` (`username`,`password`,`email`,`firstName`,`lastName`,`createDate`) VALUES (:username,:password,:email,:firstName,:lastName,:date)";
$q = $conn->prepare($sql);
$q->execute(array(
':username'=>$username,
':password'=>$hash,
':email'=>$email,
':firstName'=>$firstName,
':lastName'=>$lastName,
':date'=>$date));
?>