在二维数组中查找一列中具有特定值且另一列中具有最小值的行

Question

我有以下二维数组，如果

[0]

等于

done

，我想获得

no

列中最小值的键。

$graph= array(
"CityA" => array(
    "0" => "1",
    "1" => "CityC",
    "done" => "no",
    ),
"CityB" => array(
    "0" => "4",
    "1" => "CityA",
    "done" => "no",
    ),
"CityC" => array(
    "0" => "5",
    "1" => "CityA",
    "done" => "no",
    ),
);

Answer 1

试试这个，

$arr = array_map(function($v){return $v[0];}, $graph);
$key = array_keys($arr, min($arr));

Answer 2

给你。

$tes = min( array_column( $graph, 0 ) );
$key = array_search( $tes, array_column( $graph, 0 ) );
$array_keys = array_keys($graph);

echo $array_keys[$key];

Answer 3

您应该通过阵列一次性执行所有检查。

我的代码片段将提供第一个符合条件的（包含最低的

[0]

值并且具有

done

值

no

）行的键。

代码：（演示）

$graph = [
    "CityB" => ["0" => "1", "1" => "CityA", "done" => "no"],
    "CityA" => ["0" => "1", "1" => "CityC", "done" => "no"],
    "CityD" => ["0" => "1", "1" => "CityD", "done" => "yes"],
    "CityC" => ["0" => "5", "1" => "CityA", "done" => "no"]
];

$result = [];
foreach ($graph as $key => $row) {
    if ($row['done'] === 'no' && (!isset($result[$key]) || $row[0] < $result[$key])) {
        $result[$key] = $row[0];
    }
}

echo key($result) ?? 'No "done => no" rows';

输出：

CityB