我想在我的 i18n-ed 应用程序中显示 7 个工作日的列表:
Sunday, Monday, Tuesday... Saturday
我依靠 Intl 全局对象来格式化日期/时间,但我找不到一种简单的方法来获取仅工作日名称。
我想我可以在 EPOCH 时间中添加一些天,以达到一周的第一天,但我找不到只打印工作日的格式化程序。
var date = new Date(0);
date.setDate(4 + day);
for (var i = 0; i < 7; i++) {
var weekday = new Intl.DateTimeFormat(["en"], {
weekday: "short" // ?? what should I put here
}).format(date);
console.log(weekday);
}
输出:
Sunday, January 4, 1970
Monday, January 5, 1970
Tuesday, January 6, 1970
Wednesday, January 7, 1970
Thursday, January 8, 1970
Friday, January 9, 1970
Saturday, January 10, 1970
所需输出:
Sunday
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
我也想要一个较短版本的日子,例如
Sun, Mon, Tue...
。
或者,有没有办法从 Intl
获取工作日
strings?我尝试通过控制台探索该对象,但找不到它们。
我被误导了,因为我使用的是 Intl polyfill,它还不支持
{ weekday: "short" }
作为选项。
使用本机 Intl 实现可以按预期工作。
/**
* Return list of days
* 🌍 localeName : name of local, f.e. en-GB, default es-MX
* ✅ weekday : format of weekday short/long (Default)
*/
function daysForLocale(localeName = 'es-MX', weekday = 'long') {
const {format} = new Intl.DateTimeFormat(localeName, { weekday });
return [...Array(7).keys()]
.map((day) => format(new Date(Date.UTC(2021, 5, day))));
}
// ##############################################################
// testing daysForLocale function
// ##############################################################
console.log(daysForLocale());
// ['domingo','lunes',...,'viernes','sábado']
console.log(daysForLocale('en-GB', 'short'));
// ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri','Sat']
console.log(daysForLocale('ja-JP', 'short'));
// ['日', '月', '火','水', '木', '金','土']
const weekdayDateMap = {
Mon: new Date('2020-01-06T00:00:00.000Z'),
Tue: new Date('2020-01-07T00:00:00.000Z'),
Wed: new Date('2020-01-08T00:00:00.000Z'),
Thu: new Date('2020-01-09T00:00:00.000Z'),
Fri: new Date('2020-01-10T00:00:00.000Z'),
Sat: new Date('2020-01-11T00:00:00.000Z'),
Sun: new Date('2020-01-12T00:00:00.000Z'),
};
const shortWeekdays = Object.keys(weekdayDateMap);
const getDayOfWeek = (shortName, locale = 'en-US', length = 'short') =>
new Intl.DateTimeFormat(locale, { weekday: length }).format(weekdayDateMap[shortName]);
const getDaysOfWeek = (locale = 'en-US', length = 'short') =>
shortWeekdays.map(shortName => getDayOfWeek(shortName, locale, length));
console.log(getDayOfWeek('Mon', 'de-DE')) // "Mo"
console.log(getDaysOfWeek('de-DE')) // ["Mo", "Di", "Mi", "Do", "Fr", "Sa", "So"]
注:
如果您每秒多次调用
Intl.DateTimeFormat
格式化程序,则创建一次格式化程序并重复使用它会更有效。
Intl
(因此Intl.js
)还没有一个 API 来获取工作日名称,所以你必须使用正确的选项来查询一堆天。未来可能会添加对此的支持,但现在你基本上不走运。 (至少,除非您通过修复手动增强Intl.js
。)
尝试改进最受欢迎的答案;顺便回答一下问题:
为什么要用 Date.UTC(2021, 1, day+1) 来初始化?
因为,您需要找到一个实际的日历周,您可以从中提取工作日字符串。
function getWeekdayLocale(localeName = 'fr', weekday = 'long') {
const format = new Intl.DateTimeFormat(localeName, { weekday }).format;
return [...Array(7).keys()]
.map((day) => format(new Date(Date.UTC(2021, 1, day+1))));
}
console.log(getWeekdayLocale())
这是一个不必硬编码开始日期的版本
const format = (date) => new Intl.DateTimeFormat('ca', { 'weekday': 'long' }).format(date);
const d = new Date();
d.setHours(15, 0, 0, 0); /* normalise */
d.setDate(d.getDate() - d.getDay() - 1); /* Saturday */
const localeDayNames = [...Array(7)]
.map((_, i) => format(d.setDate(d.getDate() + 1)));
console.log(localeDayNames);
如果您不想使用周日到周六的硬编码日期,请使用以下带有
date-fns
和 Intl.DateTimeFormat
的解决方案。
import { startOfWeek, addDays } from 'date-fns'
export const getDaysOfWeek = (locale: string) => {
const daysOfWeek = []
const startDate = startOfWeek(new Date())
const formatter = new Intl.DateTimeFormat(locale, { weekday: 'short' })
for (let i = 0; i < 7; i += 1) {
daysOfWeek.push(formatter.format(addDays(startDate, i)))
}
return daysOfWeek
}
更简单的解决方案:
let d = new Date();
let day_options = {
timeZone: "America/New_York",
weekday:"short"
};
let formatter = new Intl.DateTimeFormat([],day_options);
console.log(formatter.format(d));
输出:周四