在“INSERT INTO ... SELECT”查询中混合值

Question

假设我想插入评论，评论表需要一个

customer_id

，但我只有

email

。我不想事先在单独的查询中选择客户。

来自

orm/query-builder.html#inserting-data

的 INSERT INTO ... SELECT 查询看起来正是我想要的。

但是如何提供查询第一部分中选择的值之外的值？

1. 我试过：

    $select = $customersTable->find()
        ->select(['customer_id'])
        ->where(['email' => '[email protected]']);
    $query = $this->query()
        ->insert(['customer_id', 'data'])
        ->values($select)
        ->values(['data' => 'test 123'])
        ->execute();
   

   我得到：你不能在插入中混合子查询和数组数据

2. 我试过：

    $select = $customersTable->find()
        ->select(['customer_id', '"test" AS `data`'])
        ->where(['email' => 'username@example']);
    $query = $this->query()
        ->insert(['customer_id', 'data'])
        ->values($select)
        ->execute();
   

   我得到了：

   Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '`` AS `Customers__"test" AS `data`` FROM `customer` `Customers` ' at line 1
   
   INSERT INTO `comments` (`customer_id`, `data`) SELECT `Customers`.`customer_id` AS `Customers__customer_id`, `Customers."test" AS `data`` AS `Customers__"test" AS `data`` FROM `customer` `Customers` WHERE `email` = :c0
   

请帮忙

Answer 1

SELECT

子句中的自定义别名字段可以通过常规

key => value

数组语法定义，其中键将用作别名。

还要确保让驱动程序引用数据，因为它将按原样插入，否则很容易出现 SQL 注入！

$select = $customersTable->find()
    ->select([
        'customer_id',
        'data' => $customersTable->getConnection()->quote('test')
    ])
    ->where(['email' => 'username@example']);

另请参阅

• Cookbook > 数据库访问和 ORM > 查询生成器 > 选择数据